Finding the Modular Reciprocal with JavaScript

I am attempting to find the value of d by solving the equation ed ≡ 1 mod((p-1)(q-1)), similar to the RSA algorithm.

Given e = 5 and (p-1)*(q-1) = 249996

I have experimented with various Javascript code snippets, such as:

function calculateModInverse(){
var e = 5;
var p = 499;
var q = 503;
var d = e.modInverse((p-1) * (q-1));
DisplayResult(d, "privateKeyResultLabel")
}

or

function calculateModInverse(){ 
System.out.println(BigInteger.valueOf(5).modInverse(BigInteger.valueOf(249996)));
}

As of now, I am struggling to determine the correct method for calculating d, the modular inverse, in javascript.

Answer №1

While researching the concept of modular multiplicative inverse, I came across some interesting insights:

ax = 1 (mod m)
=> This implies that m divides ax - 1, and x is the sought-after inverse
=> Expressing it as ax - 1 = q*m (where q is an integer)
An essential condition here is gcd(a, m) = 1, indicating that a and m are co-prime.

In your scenario:

ed = 1 mod((p-1)(q-1)) // Given values for p, q, and e
=> Simplified to ed - 1 = z*((p-1)(q-1)) // where z is an unknown integer representing d

Referencing the Wikipedia article, one can employ the extended Euclidean GCD Algorithm to calculate the modular inverse through:

ax + by = g, with g being the gcd(a,b), assuming a and b are co-prime
// The extended GCD algorithm provides the values of x and y.

For this specific case, the equation would resemble:

ed - z*((p-1)(q-1)) = 1; // Aligning it with the structure mentioned above

a -> e
x -> d
b -> (p-1)(q-1)
y -> z

By implementing this algorithm, we can determine the values of d and z.

The extended gcd algorithm for ax + by = gcd(a,b) might follow a pattern similar to (source):

function xgcd(a, b) { 

  if (b == 0) {
    return [1, 0, a];
  }

  temp = xgcd(b, a % b);
  x = temp[0];
  y = temp[1];
  d = temp[2];
  return [y, x-y*Math.floor(a/b), d];
}

This algorithm operates in time complexity O(log(m)^2), providing efficiency compared to exponentiation.

In javascript, there may not be a built-in function for this process. Encouraging exploration of algorithms, you could experiment with adapting the code to accommodate your data range, helping you progress in the right direction.

Answer №2

The modular inverse implementation provided here is versatile, allowing for any type of inputs to be accepted. In the case of unsupported input types, the function will return `NaN`. It's worth noting that this implementation does not make use of recursion.

function modInverse(a, m) {
  // validate inputs
  [a, m] = [Number(a), Number(m)]
  if (Number.isNaN(a) || Number.isNaN(m)) {
    return NaN // invalid input
  }
  a = (a % m + m) % m
  if (!a || m < 2) {
    return NaN // invalid input
  }
  // find the gcd
  const s = []
  let b = m
  while(b) {
    [a, b] = [b, a % b]
    s.push({a, b})
  }
  if (a !== 1) {
    return NaN // inverse does not exist
  }
  // find the inverse
  let x = 1
  let y = 0
  for(let i = s.length - 2; i >= 0; --i) {
    [x, y] = [y,  x - y * Math.floor(s[i].a / s[i].b)]
  }
  return (y % m + m) % m
}

// Tests
console.log(modInverse(1, 2))       // = 1
console.log(modInverse(3, 6))       // = NaN
console.log(modInverse(25, 87))     // = 7
console.log(modInverse(7, 87))      // = 25
console.log(modInverse(19, 1212393831))     // = 701912218
console.log(modInverse(31, 73714876143))    // = 45180085378
console.log(modInverse(3, 73714876143))     // = NaN
console.log(modInverse(-7, 87))     // = 62
console.log(modInverse(-25, 87))    // = 80
console.log(modInverse(0, 3))       // = NaN
console.log(modInverse(0, 0))       // = NaN

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