const names = ["Daniel", "Lucas", "Gwen", "Henry", "Jasper"];
const random = ["hi", "Lucas", "apple", "banana", "Jasper", "hello", "meow"];
I am looking to compare the arrays names and random. If there are any duplicates in the random array, I want to remove them and achieve an outcome like this:
const newArr = ["hi", "apple", "banana", "hello", "meow"]
Can you guide me on how to accomplish this?
const names = ["Emma", "Ethan", "Ava", "Mia", "Oliver"];
const random = ["hello", "Ethan", "kiwi", "pear", "Oliver", "hey", "woof"];
const result = random.filter(name => !names.includes(name))
console.log(result)This is just a basic filter function
const filteredArray = random.filter(item => !names.includes(item))
If you're looking to eliminate duplicates from a list, one way to do it is by using the filter method like so:
const newArr = random.filter(name => ! names.includes(name));
This approach works well for a small number of values, but may not be efficient for larger datasets.
The time complexity of this method is O(n^2), where n represents the size of both lists. Each element in random is compared against all elements in names.
For handling a large amount of data, consider implementing a Map structure instead.
const names = ["Daniel", "Lucas", "Gwen", "Henry", "Jasper"];
const random = ["hi", "Lucas", "apple", "banana", "Jasper", "hello", "meow"];
const namesMap = new Map();
for (const name of names) namesMap.set(name, true);
const newArr = [];
for (const rand of random) {
if (namesMap.has(rand)) continue;
newArr.push(rand);
}
Despite the additional loop, the overall time complexity remains O(n) due to the iteration through both lists, which simplifies to O(2n) or just O(n).
Keep in mind that while this method is more efficient for larger datasets, it might sacrifice some readability.
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