Looking for a way to create a function that will return a number under 100? Check out the code snippet below:
const myArray = ['hello', 3, true, 18, 10,, 99 'ten', false]
const isLessThan100 = (array) => {
// Insert solution here
}
I believe the filter method might be useful in this case, but unsure on how to specifically filter for a number less than 100 and not a string.
Any help would be greatly appreciated!
To determine if a value is a number, you can use the following method:
const myArray = ['hello', 3, true, 18, 10, 99, 'ten', false];
const lessThan100 = myArray.filter(item => {
return (typeof item === "number") && item < 100;
});
Check out this concise example utilizing the filter method:
const myArray = ['hello', 3, true, 18, 10, 99, 101, 'ten', false];
const numbersLessThan100 = a => a.filter(e => +e === e && e < 100);
console.log(numbersLessThan100(myArray));The typeof operator is used to determine the type of the operand without evaluating it.
Before checking if an item is a number and less than 100, you can first use the typeof operator.
To shorten the code, you can write it in a single line by omitting the curly braces.
Consider using Array.prototype.filter() like this:
const myArray = ['hello', 3, true, 18, 10,, 99, 'ten', false]
const isLessThan100 = (array) => array.filter(num => typeof(num) === "number" && num < 100);
console.log(isLessThan100(myArray))const isLessThan100 = (array)When looking to retrieve a single value from an array, considering reducing the array may be beneficial.
const
array = ['hello', 3, true, 18, 10,, 99, 'ten', false],
findValueLessThan100 = array => array.reduce((result, value) =>
typeof value === 'number' && value < 100 && (typeof result !== 'number' || value > result)
? value
: result,
undefined);
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