Find and compare certain data points within a single line

Question

Find and compare certain data points within a single line

My goal is to extract specific values from a URL, focusing on the parameters and their respective values.

Since a parameter can appear multiple times in the URL, I need to retrieve all instances along with their corresponding values.

&myparameter[123]=1&myparameter[678]=4

The desired output should be ;123;1,;678;4

I attempted the following code, but I require the results to be comma-separated pairs rather than individual ones.

var regex1 = /&myparameter\[(.*?)\]=/g;
var regex2 = /\]=(.*?)\&/g;
var input = '&myparameter[123]=1&myparameter[678]=4&otherthings=rtz';
var match;
var y = [];
do {
  match = regex1.exec(input);
  match2 = regex2.exec(input);
  if (match) {
    var x = match[1];
    var c = match2[1];
    var pair = ';' + x + ';' + c;
    console.log(pair);
  }
} while (match);

How can I combine these results or suggest a more efficient method? Thank you.

javascript arrays

Answer 1

Answer №1

In the loop, simply add your values to an array and then use them outside the loop as necessary.

The following code assumes that you need to create an array of pairs that can be joined with commas later on. There is also a commented section that directly builds a string if that's the desired approach.

Here is how you can achieve this with minimal modifications to your existing code:

var regex1 = /&myparameter\[(.*?)\]=/g;
var regex2 = /\]=(.*?)\&/g;
var input = '&myparameter[123]=1&myparameter[678]=4&otherthings=rtz';
var match;
var y = [];
// var y = ''; // if building a string instead
do {
  match = regex1.exec(input);
  match2 = regex2.exec(input);
  if (match) {
    var x = match[1];
    var c = match2[1];
    y.push(';' + x + ';' + c);
    // or, if `y` is a string, `y += ';' + x + ';' + c;
  }
} while (match);

console.log(y.join(','));
// console.log(y); if building a string

Answer 2

In the loop, simply add your values to an array and then use them outside the loop as necessary.

The following code assumes that you need to create an array of pairs that can be joined with commas later on. There is also a commented section that directly builds a string if that's the desired approach.

Here is how you can achieve this with minimal modifications to your existing code:

var regex1 = /&myparameter\[(.*?)\]=/g;
var regex2 = /\]=(.*?)\&/g;
var input = '&myparameter[123]=1&myparameter[678]=4&otherthings=rtz';
var match;
var y = [];
// var y = ''; // if building a string instead
do {
  match = regex1.exec(input);
  match2 = regex2.exec(input);
  if (match) {
    var x = match[1];
    var c = match2[1];
    y.push(';' + x + ';' + c);
    // or, if `y` is a string, `y += ';' + x + ';' + c;
  }
} while (match);

console.log(y.join(','));
// console.log(y); if building a string

Answer 3

Answer №2

Check out my Gist on extracting URL parameters as a JavaScript object. It's condensed into just one line of code, although it may not handle repeated parameters well. Still worth exploring!

console.log( JSON.parse('{"' + decodeURI(window.location.href.replace(/^(.*\?)/, '').replace(/&/g, "\",\"").replace(/=/g,"\":\"")) + '"}') );

Answer 4

Check out my Gist on extracting URL parameters as a JavaScript object. It's condensed into just one line of code, although it may not handle repeated parameters well. Still worth exploring!

console.log( JSON.parse('{"' + decodeURI(window.location.href.replace(/^(.*\?)/, '').replace(/&/g, "\",\"").replace(/=/g,"\":\"")) + '"}') );

Answer 5

Answer №3

To simplify the process, use a single regex pattern with capture groups. Each iteration involves pushing the matched string into an array, followed by joining them together:

var regex = /&myparameter\[(.*?)\]=(\d+)/g;
var input = '&myparameter[123]=1&myparameter[678]=4&otherthings=rtz';
var y = [];
var match;
while ((match = regex.exec(input)) !== null) {
  y.push(';' + match[1] + ';' + match[2]);
}

var result = y.join(',');

console.log(result);

Answer 6

To simplify the process, use a single regex pattern with capture groups. Each iteration involves pushing the matched string into an array, followed by joining them together:

var regex = /&myparameter\[(.*?)\]=(\d+)/g;
var input = '&myparameter[123]=1&myparameter[678]=4&otherthings=rtz';
var y = [];
var match;
while ((match = regex.exec(input)) !== null) {
  y.push(';' + match[1] + ';' + match[2]);
}

var result = y.join(',');

console.log(result);

Answer 7

Answer №4

let pattern = new RegExp(/&myparameter\[([0-9]+)\]=([0-9]+)/,'g');
let string = '&myparameter[123]=1&myparameter[678]=4&otherthings=rtz';

let match;
let result = '';
while ((match = pattern.exec(string)) !== null) {  
    result += ';' + match[1] + ';' + match[2] + ',';
}
console.log(result);

Answer 8

let pattern = new RegExp(/&myparameter\[([0-9]+)\]=([0-9]+)/,'g');
let string = '&myparameter[123]=1&myparameter[678]=4&otherthings=rtz';

let match;
let result = '';
while ((match = pattern.exec(string)) !== null) {  
    result += ';' + match[1] + ';' + match[2] + ',';
}
console.log(result);

Find and compare certain data points within a single line

Answer №1

Answer №2

Answer №3

Answer №4

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