In Javascript, I want to find a number in an array. If the number does not exist in the array, I need to return a number that is lower than the target number.
In Javascript, I want to find a number in an array. If the number does not exist in the array, I need to return a number that is lower than the target number.
This unique function is designed to locate the largest array element that is equal to or slightly less than the specified value. In simple terms, if the specified value exists in the array, it will be returned. If not, the function will return the largest value in the array that is still smaller than the target value. To put it another way, you will receive the largest value that is not greater than the target value.
Upon execution, the function will provide both the value and the position (index) of the identified element in the array. While there may be multiple elements with the same value in the array, the function will return the index of the first occurrence.
function getBiggestElementNoBiggerThan(arr, x) { // Search for element x in Array arr.
if (arr.length == 0) { // The array must not be empty,
return null; // otherwise the result is null.
}
var best = { value: arr[0], index: 0 }, // Start with the first element.
n = arr.length;
for (var i = 1; i < n; ++i) { // Check the rest of the elements.
if (arr[i] == x) { // Have we found the desired value?
return { value: x, index: i };
} else if (arr[i] > x) { // If not, is this better than our current best?
best = { value: arr[i], index: i }; // Take note that if multiple values are equally good,
} // the index of the earliest one is selected.
}
return best; // Return the best value found.
}
function test(arr, x) {
var result = getBiggestElementNoBiggerThan(arr, x);
document.write('the largest element in '+arr.join(', ')+' that is not less than '+
x+' is: '+result.value+' at index '+result.index+'<br />');
}
document.write('Test cases: <br />');
test([3, 1, 4, 1, 5, 9], 1);
test([3, 1, 4, 1, 5, 9], 5);
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