Filter out the truthy values in an array with JavaScript

I am currently working with a javascript array called 'foo' which looks like this:

var foo = [false,false,true,false,true];

My goal is to eliminate all the 'true' values and only keep the 'false' ones, resulting in this array:

[false,false,false]

I attempted to achieve this using the following code:

console.log(foo.map(function(i){if(i==false)return i;}));

However, the output I received was:

[ false, false, undefined, false, undefined ]

Do you have any suggestions on how I can successfully accomplish this task?

Answer №1

let examples = [0, 1, 2, 3, 4];
let filterResult = examples.filter(function(item) {
    return item > 2;
});

console.log(filterResult);

Answer №2

For this task, it is recommended to use filter instead of map.

var foo = [false,false,true,false,true];
console.log(foo.filter(function(i){ return i !== true; }));

This code snippet effectively filters out true values, aligning with the requirements of your question. Feel free to modify the filter condition as needed for different scenarios.

Answer №3

Try using the filter method

var bar = [true, false, true, true, false];
var filteredArray = bar.filter(function(element) {
  return element === true;
});
console.log(filteredArray)

Check out the DEMO here!

Answer №4

Looking for a simple solution using RamdaJS? Check out this example:

const data = [true, false, 0, '', 'hello'];
const isFalsyValue = R.filter(R.not);
const result = isFalsyValue(data);

//output: [false, 0, '']

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