Filter out specific fields from an object when populating in MongoDB using the aggregate method

Is there a way to use the populate() function in MongoDB to exclude specific fields like email and address, and only retrieve the name?

For example:

const results = await Seller.aggregate(aggregatePipeline).exec();
const sellers = await Seller.populate(results, { path: "user" });

Instead of getting all fields when populating the user:

...
user: {
    email: "[email protected]",
    address:{},
    name: "name"
}

I want to exclude certain data and only get the name:

...
user: {
   name: "name"
}

Answer №1

You have two options:

const sellers = await Seller.populate(results, { path: "user", select: '- 
email -address'  });

or

const sellers = await Seller.populate(results, { path: "user", select: 
'name'  });

Answer №2

After reviewing the mongoose documentation at https://mongoosejs.com/docs/populate.html, I have learned that populate, similar to $lookup, is used to resolve relationships with other collections.

MongoDB introduced the join-like $lookup aggregation operator in versions >= 3.2. However, Mongoose offers a more robust solution called populate(), which allows you to reference documents in different collections.

In your scenario, it seems like there is no need to establish a connection with another collection since you already have the desired data. You can utilize $project at the end of your pipeline aggregation to only retain the name field, as shown below:

{ $project: { name:1 } }

Please let me know if this explanation was helpful for you.

Edit :

Upon closer inspection, if you encounter the mentioned data result post-populate rather than post-aggregation, you can use the select function to isolate your final field. Refer to this answer for more details

user: {
    email: "<a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="7e161914163e19131f1712501d1113">[email protected]</a>",
    address:{},
    name: "name"
}

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