Failure to override prototype method

Why isn't the code `foo` displayed in the console? I expected the `foo` method in the child class to override the parent class. Why did that not happen?

function parent(){ }
parent.prototype.foo = function(){ 
    console.log('foobar');
};

function child(){ }
child.prototype.foo = function(){ 
    console.log('foo');
};

child.prototype = Object.create(parent.prototype);
child.prototype.constructor = child;

console.log(new child().foo()); // foobar

Answer №1

When you perform the following:

child.prototype = Object.create(parent.prototype)

you are actually overwriting the object that previously had a foo property.

To avoid this, simply adjust the order to assign the foo value afterwards:

function parent(){ }
parent.prototype.foo = function(){ 
    console.log('foobar');
};

function child(){ }
child.prototype = Object.create(parent.prototype);
child.prototype.foo = function(){ 
    console.log('foo');
};
child.prototype.constructor = child;

console.log(new child().foo()); // foo

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