Extracting the name of the file from the image's web address

Question

Extracting the name of the file from the image's web address

I have created a simple Chrome extension for personal use and sharing with friends. I am dealing with URLs that have various formats, such as:

i.imgur.com/abcd123.png or imgur.com/a2b3c78 or even i.imgur.com/herp321.png?1

All I need from these URLs are the 7-character codes before the file extensions. For example, abcd123, a2b3c78, and herp321.

I have tried using .replace but it doesn't handle exceptions like the third example. I also attempted to use regex, but couldn't get it to work properly. The only constant part of the URL is the following format, with the code represented as x:

imgur.com/xxxxxxxx

The beginning and end of the URL may vary, but the above format remains consistent. Is there a way to extract just the alphanumeric filename from the examples provided, regardless of what comes before the URL or any additional modifications/extensions?

javascript regex imgur

Answer 1

Answer №1

imgurLink=str.match(/imgur.com\/(.{7})/);
//The result can be found in imgurLink[1]

Answer 2

imgurLink=str.match(/imgur.com\/(.{7})/);
//The result can be found in imgurLink[1]

Answer 3

Answer №2

Here's a straightforward solution:

 let imageLink = 'i.imgur.com/derp456.png?1'
 let pattern = /imgur\.com\/(\w{7})/;
 
 console.log(imageLink.match(pattern)[1]);

Answer 4

Here's a straightforward solution:

 let imageLink = 'i.imgur.com/derp456.png?1'
 let pattern = /imgur\.com\/(\w{7})/;
 
 console.log(imageLink.match(pattern)[1]);

Answer 5

Answer №3

You might want to consider using the following regex pattern in your code:

/.+\/([a-z0-9]+).+/

If you are working in JavaScript, you can implement it like this:

var imageUrl = 'i.imgur.com/dsf8635235.png?sdgdsgdsg'
  , results = imageUrl.match( /.+\/([a-z0-9]+).+/ );

console.log( results[ 1 ] ); // dsf8635235

There are several variations you could try as well:

console.log( 'imgur.com/dsf8635235'.match( /.+\/([a-z0-9]+).+/ )[ 1 ] ); // dsf8635235
console.log( 'i.imgur.com/dsf8635235'.match( /.+\/([a-z0-9]+).+/ )[ 1 ] ); // dsf8635235
console.log( 'imgur.com/dsf8635235?1'.match( /.+\/([a-z0-9]+).+/ )[ 1 ] ); // dsf8635235

Feel free to experiment with these patterns and see what works best for your specific scenario.

Answer 6

You might want to consider using the following regex pattern in your code:

/.+\/([a-z0-9]+).+/

If you are working in JavaScript, you can implement it like this:

var imageUrl = 'i.imgur.com/dsf8635235.png?sdgdsgdsg'
  , results = imageUrl.match( /.+\/([a-z0-9]+).+/ );

console.log( results[ 1 ] ); // dsf8635235

There are several variations you could try as well:

console.log( 'imgur.com/dsf8635235'.match( /.+\/([a-z0-9]+).+/ )[ 1 ] ); // dsf8635235
console.log( 'i.imgur.com/dsf8635235'.match( /.+\/([a-z0-9]+).+/ )[ 1 ] ); // dsf8635235
console.log( 'imgur.com/dsf8635235?1'.match( /.+\/([a-z0-9]+).+/ )[ 1 ] ); // dsf8635235

Feel free to experiment with these patterns and see what works best for your specific scenario.

Answer 7

Answer №4

To implement this functionality, you can utilize the match function along with a regular expression.

UPDATE:

Here's a possible solution:

var links = ["i.imgur.com/abcd123.png", "imgur.com/a2b3c78", "i.imgur.com/herp321.png?1"];
var pattern =  /\/(.{7})/;

for(i=0;i<links.length;i++) {
  pattern.exec(links[i]);
  console.log(RegExp.$1);
}

Answer 8

To implement this functionality, you can utilize the match function along with a regular expression.

UPDATE:

Here's a possible solution:

var links = ["i.imgur.com/abcd123.png", "imgur.com/a2b3c78", "i.imgur.com/herp321.png?1"];
var pattern =  /\/(.{7})/;

for(i=0;i<links.length;i++) {
  pattern.exec(links[i]);
  console.log(RegExp.$1);
}

Extracting the name of the file from the image's web address

Answer №1

Answer №2

Answer №3

Answer №4

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