Extracting information from a complicated and unreliable JSON structure

Question

Extracting information from a complicated and unreliable JSON structure

Dealing with a JSON object retrieved via POST query, I am facing the challenge of setting variables due to the varying order of results. This inconsistency is causing issues with my variable assignment based on array positions:

var idle = Example1.results[0].data[1].stats.count;
var waiting = Example1.results[1].data[0].stats.count;

(For instance, this setup works for example 1 but not example 2)

Example1 = {"results":[{"group":{"queueId":"someID"},"data":[{"metric":"oOnQueueUsers","qualifier":"INTERACTING","stats":{"count":2}},{"metric":"oOnQueueUsers","qualifier":"IDLE","stats":{"count":5}}]},{"group":{"queueId":"someID","mediaType":"voice"},"data":[{"metric":"oWaiting","stats":{"count":0}}]}]}

Example2 = {"results":[{"group":{"queueId":"someID","mediaType":"voice"},"data":[{"metric":"oWaiting","stats":{"count":1}}]},{"group":{"queueId":"someID"},"data":[{"metric":"oOnQueueUsers","qualifier":"INTERACTING","stats":{"count":4}},{"metric":"oOnQueueUsers","qualifier":"IDLE","stats":{"count":6}}]}]}

javascript arrays json

Answer 1

Answer №1

If the order of data is not consistent or if objects have different properties, it's best not to search for specific data in the resultant JSON.

Instead, create a custom data structure to search/index against and then iterate through the JSON, mapping each element to your new structure as needed.

For example:

var exampleResults1 = {
  // example JSON data
}

var newDataSource = {
  parseResults: function(resultObj) {
    // parsing logic here
  }
};

newDataSource.parseResults(exampleResults1);
console.log(JSON.stringify(newDataSource));

Running this code will show you how the new data structure looks after populating it with values from the original JSON object. The keys in the new structure correspond to values from the original data.

This sample code may not cover all data points in your results, but it demonstrates the importance of understanding the returned data and structuring it appropriately based on the actual results.

Answer 2

If the order of data is not consistent or if objects have different properties, it's best not to search for specific data in the resultant JSON.

Instead, create a custom data structure to search/index against and then iterate through the JSON, mapping each element to your new structure as needed.

For example:

var exampleResults1 = {
  // example JSON data
}

var newDataSource = {
  parseResults: function(resultObj) {
    // parsing logic here
  }
};

newDataSource.parseResults(exampleResults1);
console.log(JSON.stringify(newDataSource));

Running this code will show you how the new data structure looks after populating it with values from the original JSON object. The keys in the new structure correspond to values from the original data.

This sample code may not cover all data points in your results, but it demonstrates the importance of understanding the returned data and structuring it appropriately based on the actual results.

Answer 3

Answer №2

If you utilize the find() and some() methods, you can achieve the desired outcome.

const example1 = { results: [ { group: { queueId: "someID" }, data: [ { metric: "oOnQueueUsers", qualifier: "INTERACTING", stats: { count: 2 }, }, { metric: "oOnQueueUsers", qualifier: "IDLE", stats: { count: 5 } }, ], }, { group: { queueId: "someID", mediaType: "voice" }, data: [{ metric: "oWaiting", stats: { count: 0 } }], }, ], }; 

const example2 = { results: [ { group: { queueId: "someID", mediaType: "voice" }, data: [{ metric: "oWaiting", stats: { count: 1 } }], }, { group: { queueId: "someID" }, data: [ { metric: "oOnQueueUsers", qualifier: "INTERACTING", stats: { count: 4 }, }, { metric: "oOnQueueUsers", qualifier: "IDLE", stats: { count: 6 } }, ], }, ], };

const idle1 = example1.results
  .find(a => a.data.some(d => d.qualifier === "IDLE"))
  .data.find(b => b.qualifier === "IDLE").stats.count;

const waiting1 = example1.results
  .find(a => a.data.some(d => d.metric === "oWaiting"))
  .data.find(b => b.metric === "oWaiting").stats.count;

const idle2 = example2.results
  .find(a => a.data.some(d => d.qualifier === "IDLE"))
  .data.find(b => b.qualifier === "IDLE").stats.count;

const waiting2 = example2.results
  .find(a => a.data.some(d => d.metric === "oWaiting"))
  .data.find(b => b.metric === "oWaiting").stats.count;

console.log({ idle1 }, { waiting1 }, { idle2 }, { waiting2 });

Answer 4

If you utilize the find() and some() methods, you can achieve the desired outcome.

const example1 = { results: [ { group: { queueId: "someID" }, data: [ { metric: "oOnQueueUsers", qualifier: "INTERACTING", stats: { count: 2 }, }, { metric: "oOnQueueUsers", qualifier: "IDLE", stats: { count: 5 } }, ], }, { group: { queueId: "someID", mediaType: "voice" }, data: [{ metric: "oWaiting", stats: { count: 0 } }], }, ], }; 

const example2 = { results: [ { group: { queueId: "someID", mediaType: "voice" }, data: [{ metric: "oWaiting", stats: { count: 1 } }], }, { group: { queueId: "someID" }, data: [ { metric: "oOnQueueUsers", qualifier: "INTERACTING", stats: { count: 4 }, }, { metric: "oOnQueueUsers", qualifier: "IDLE", stats: { count: 6 } }, ], }, ], };

const idle1 = example1.results
  .find(a => a.data.some(d => d.qualifier === "IDLE"))
  .data.find(b => b.qualifier === "IDLE").stats.count;

const waiting1 = example1.results
  .find(a => a.data.some(d => d.metric === "oWaiting"))
  .data.find(b => b.metric === "oWaiting").stats.count;

const idle2 = example2.results
  .find(a => a.data.some(d => d.qualifier === "IDLE"))
  .data.find(b => b.qualifier === "IDLE").stats.count;

const waiting2 = example2.results
  .find(a => a.data.some(d => d.metric === "oWaiting"))
  .data.find(b => b.metric === "oWaiting").stats.count;

console.log({ idle1 }, { waiting1 }, { idle2 }, { waiting2 });

Extracting information from a complicated and unreliable JSON structure

Answer №1

Answer №2

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