While diving into Eloquent JS, I stumbled upon this code snippet that left me puzzled. The explanation given didn't quite click with me, so I'm reaching out for some clarification on why the second console.log returns the value it does.
Take a look at the code below:
var listOfNumbers = [2, 3, 5, 7, 11];
console.log(listOfNumbers[1]);
// → 3
console.log(listOfNumbers[1 - 1]);
// → 2
Any thoughts on this?
2 stands as the initial value in the array starting at zero index
listOfNumbers[1 - 1] = listOfNumbers[0] = 2
The listNumber array holds the values 2, 3, 5, 7, and 11
listNumber[0] represents 2
listNumber[1] equals 3
listNumber[2] equals 5
listNumber[3] equals 7
listNumber[4] equals 11
listNumber[1-1] => listNumber[0] => 2console.log(listNumber[0]); //will output 2 to the consoleIn programming, arrays are typically 0 indexed. This means that the first element in an array is accessed using index 0. For example, if we have a list called list, then list[0] would refer to the first element in the list which is 2, and list[1] would refer to the second element which is 3.
The initial element in an array is referred to as [0], followed by the second one, [1]. Remember, array indexes always commence at 0.
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