Exploring the Power of Math Set Functions with Associative Arrays in Javascript

Question

Exploring the Power of Math Set Functions with Associative Arrays in Javascript

Is there a way to find the variance between two sets of objects in Javascript? For example:

var obj1[0] = { name : 'test1' , type : 'test2' };
var obj1[1] = { name : 'test2' , type : 'test3' };
var obj2[0] = { name : 'test1' , type : 'test2' };
var obj2[1] = { name : 'test3' , type : 'test4' };

I am looking to output something like this:

If Intersection() :
obj3[0] = { name : 'test1' , type : 'test2' }
If difference obj1-obj2 :
obj4[0] = { name : 'test2' , type : 'test3' };
If difference obj2-obj1 :
obj5[0] = { name : 'test3' , type : 'test4' };

My search has not yielded any results related to associative arrays.

javascript arrays associative-array intersection

Answer 1

Answer №1

function checkEquality(x, y){
       return (x.name === y.name && x.type === y.type);            
    }

    function checkPresence(array, object){
        var length = array.length;

        for(var i = 0; i < array.length; i++){
            if(checkEquality(array[i], object)) return true;                               
        }

        return false;        
    }    

    function duplicateObject(obj){
        return {
            name: obj.name,
            type: obj.type
        };        
    }


    function findIntersection(x, y){
        var commonElements = [];    
        if(!x.length || !y.length) return commonElements;

        var lengthX = x.length;
        for(var i = 0; i < lengthX; i++){
            if(checkPresence(y, x[i])){
                commonElements.push(duplicateObject(x[i]));   
            }            
        }

        return commonElements;              
    }




    function findDifference(x, y){
       var resultArray = [];    
        if(!x.length || !y.length) return resultArray;

        var commonElements = findIntersection(x, y);
        var lengthX = x.length;

        for(var i = 0; i < lengthX; i++){
            if(!checkPresence(commonElements, x[i])){
                resultArray.push(duplicateObject(x[i]));   
            }               
        }

        return resultArray;
    }

    var array1 = [{ name : 'test1' , type : 'test2' },{ name : 'test2' , type : 'test3' }];

    var array2 = [{ name : 'test1' , type : 'test2' }, { name : 'test3' , type : 'test4' }];

    console.log(findIntersection(array1, array2));
    console.log(findDifference(array1, array2));
    console.log(findDifference(array2, array1));

Answer 2

function checkEquality(x, y){
       return (x.name === y.name && x.type === y.type);            
    }

    function checkPresence(array, object){
        var length = array.length;

        for(var i = 0; i < array.length; i++){
            if(checkEquality(array[i], object)) return true;                               
        }

        return false;        
    }    

    function duplicateObject(obj){
        return {
            name: obj.name,
            type: obj.type
        };        
    }


    function findIntersection(x, y){
        var commonElements = [];    
        if(!x.length || !y.length) return commonElements;

        var lengthX = x.length;
        for(var i = 0; i < lengthX; i++){
            if(checkPresence(y, x[i])){
                commonElements.push(duplicateObject(x[i]));   
            }            
        }

        return commonElements;              
    }




    function findDifference(x, y){
       var resultArray = [];    
        if(!x.length || !y.length) return resultArray;

        var commonElements = findIntersection(x, y);
        var lengthX = x.length;

        for(var i = 0; i < lengthX; i++){
            if(!checkPresence(commonElements, x[i])){
                resultArray.push(duplicateObject(x[i]));   
            }               
        }

        return resultArray;
    }

    var array1 = [{ name : 'test1' , type : 'test2' },{ name : 'test2' , type : 'test3' }];

    var array2 = [{ name : 'test1' , type : 'test2' }, { name : 'test3' , type : 'test4' }];

    console.log(findIntersection(array1, array2));
    console.log(findDifference(array1, array2));
    console.log(findDifference(array2, array1));

Exploring the Power of Math Set Functions with Associative Arrays in Javascript

Answer №1

Similar questions

Eliminate the jQuery AJAX timestamp from the URL parameters

Change the ng-model of the initial controller when a button is clicked in a separate controller

Exclude weekends from DateTime

Unable to display toast notification in React/MUI/Typescript project

Utilizing dynamically assigned ng directives in my unique custom directive

c# simulating button click through injected JavaScript

Guide to combining two vectors with a scalar, storing the outcome in one vector, and returning that vector from a function in the C programming language

Confirming user credentials for every page

Vue.js v-cloak lifecycle method

Refresh the HTML webpage using AJAX technology

Having trouble accessing a React component class from a different component class

Invoke a function from a page that has been reloaded using Ajax

Show pagination control only when there are multiple pages in AngularJS using ui-bootstrap

Every single data attribute is unique for each element

We could not locate the requested resource with a DELETE request using the fetch JSON method

The header that sticks on scroll is annoyingly blocking the content

Customizing a tinyMCE button with a unique icon

Is it possible to develop a web-based chat application using socket.io without the need for ssh access or having to keep the terminal

Get a Google Sheets file in CSV format

How can I make my navbar stay fixed in place and also activate the transform scale functionality?