I am currently working with an array as shown below
var nums = ["1", "2", "2", "3", "4", "4", "5"];
My goal is to compare the values in the array and determine whether they are in ascending order or not.
In case two values in the array are identical, I should ignore them. If the order of values is incorrect (e.g. 1,3,2..), then I need to throw an error. I prefer to accomplish this using only pure JavaScript.
Appears simple:
function checkAscendingOrder(arr){
let ascending = true;
for(let index=1;index<arr.length;index++){
if(Number(arr[index]) < Number(arr[index-1])){
ascending = false;
break;
}
}
return ascending
}
Utilizing jQuery Library
let numbers = [9, 3, 7, 3, 5, 2];
let sortedNumbers = numbers.slice(0).sort(function(a,b) {
return a - b;
});
//check if array is sorted
if(numbers.join(',') === sortedNumbers.join(',')) {
//get unique elements only
let finalArray = $.grep(numbers, function(element, index) {
return index === $.inArray(element, numbers);
});
console.log(finalArray);
}
else {
console.log('Error: Array not Sorted');
}
To determine if each pair of items is in ascending order, I use the parseInt() function to convert the strings into numeric values. After looping through all pairs, I compare the incremented index value with the total number of pairs.
UPDATE: Following Rick Hitchcock's advice, instead of breaking out of the loop, I simply return false if any pair is not in ascending order or equal, and true if the entire loop completes successfully.
function checkAscendingOrder(array) {
for (var i = 0; i < (array.length - 1); i++) {
if (parseInt(array[i]) > parseInt(array[i+1])) {
return false;
}
}
return true;
}
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