Exploring the intricacies of nested objects

Question

Exploring the intricacies of nested objects

I am currently developing an API that retrieves data from an external source. After processing the business logic, I end up with the following response:

 {
  data: [
    {
      BTC: {
        USD: 46389.84,
        RUB: 3406131.15,
        EUR: 39472.76,
      },
    },
    {
      ETH: {
        USD: 3215.65,
        RUB: 235786.69,
        EUR: 2741.52,
      },
    },
  ],

}

My goal is to eliminate this nesting and simplify the result to:

 {
  data: {
    BTC: {
      USD: 46389.84,
      RUB: 3406131.15,
      EUR: 39472.76,
    },

    ETH: {
      USD: 3215.65,
      RUB: 235786.69,
      EUR: 2741.52,
    },
  },
}

javascript express

Answer 1

Answer №1

To successfully flatten the objects within the data array without nested keys with objects as values, you can utilize the following code:

const flatData = obj.data.reduce((acc, cur) => ({...cur, ...acc}), {});
const newObj = { data: flatData };

This process involves two key components:

The usage of {...cur, ...acc}: This syntax employs the spread operator (...) to unpack and merge arrays or objects together seamlessly.
Utilizing the
```
x.reduce((acc, cur) => /* new acc */, initialValue)
```
method: The reduce function allows us to transform an array into a different structure by iterating over its elements and building up an accumulating object (acc). It is important to return the updated acc in each iteration.

Answer 2

To successfully flatten the objects within the data array without nested keys with objects as values, you can utilize the following code:

const flatData = obj.data.reduce((acc, cur) => ({...cur, ...acc}), {});
const newObj = { data: flatData };

This process involves two key components:

The usage of {...cur, ...acc}: This syntax employs the spread operator (...) to unpack and merge arrays or objects together seamlessly.
Utilizing the
```
x.reduce((acc, cur) => /* new acc */, initialValue)
```
method: The reduce function allows us to transform an array into a different structure by iterating over its elements and building up an accumulating object (acc). It is important to return the updated acc in each iteration.

Answer 3

Answer №2

const result = {
    info: [
      {
        BTC: {
          USD: 46389.84,
          RUB: 3406131.15,
          EUR: 39472.76,
        },
      },
      {
        ETH: {
          USD: 3215.65,
          RUB: 235786.69,
          EUR: 2741.52,
        },
      },
    ],
  };

const newData = {
    data: {},
  };

result.info.map((item) => {
  const keys = Object.keys(item).map((key) => key);
  const values = Object.values(item).map((value) => value);
  newData.data[keys[0]] = values[0];
});

To simplify the process, consider using the reduce method or manually handling it like shown above.

Answer 4

const result = {
    info: [
      {
        BTC: {
          USD: 46389.84,
          RUB: 3406131.15,
          EUR: 39472.76,
        },
      },
      {
        ETH: {
          USD: 3215.65,
          RUB: 235786.69,
          EUR: 2741.52,
        },
      },
    ],
  };

const newData = {
    data: {},
  };

result.info.map((item) => {
  const keys = Object.keys(item).map((key) => key);
  const values = Object.values(item).map((value) => value);
  newData.data[keys[0]] = values[0];
});

To simplify the process, consider using the reduce method or manually handling it like shown above.

Answer 5

Answer №3

The deepmerge() function here provides a more comprehensive approach compared to the shallow copy obtained from using Object.assign() or the spread operator

var deepMerge = function () {

    // Setting up the merged object
    var newObj = {};

    // Merging the object into the newObj object
    var merge = function (obj) {
        for (var prop in obj) {
            if (obj.hasOwnProperty(prop)) {
                // If property is an object, merge properties
                if (Object.prototype.toString.call(obj[prop]) === '[object Object]') {
                    newObj[prop] = deepMerge(newObj[prop], obj[prop]);
                } else {
                    newObj[prop] = obj[prop];
                }
            }
        }
    };

    // Iterating over each object and performing a merge
    for (var i = 0; i < arguments.length; i++) {
        merge(arguments[i]);
    }

    return newObj;

};


const response = {
    data: [
      {
        BTC: {
          USD: 46389.84,
          RUB: 3406131.15,
          EUR: 39472.76,
          SOME_OBJ: {
            USD: 46389.84,
            RUB: 3406131.15,
            EUR: 39472.76,
          }
        },
      },
      {
        ETH: {
          USD: 3215.65,
          RUB: 235786.69,
          EUR: 2741.52,
        },
      },
    ],
}

let deepData = {};

response.data.forEach(obj => { deepData = deepMerge(obj, deepData); })

Answer 6

The deepmerge() function here provides a more comprehensive approach compared to the shallow copy obtained from using Object.assign() or the spread operator

var deepMerge = function () {

    // Setting up the merged object
    var newObj = {};

    // Merging the object into the newObj object
    var merge = function (obj) {
        for (var prop in obj) {
            if (obj.hasOwnProperty(prop)) {
                // If property is an object, merge properties
                if (Object.prototype.toString.call(obj[prop]) === '[object Object]') {
                    newObj[prop] = deepMerge(newObj[prop], obj[prop]);
                } else {
                    newObj[prop] = obj[prop];
                }
            }
        }
    };

    // Iterating over each object and performing a merge
    for (var i = 0; i < arguments.length; i++) {
        merge(arguments[i]);
    }

    return newObj;

};


const response = {
    data: [
      {
        BTC: {
          USD: 46389.84,
          RUB: 3406131.15,
          EUR: 39472.76,
          SOME_OBJ: {
            USD: 46389.84,
            RUB: 3406131.15,
            EUR: 39472.76,
          }
        },
      },
      {
        ETH: {
          USD: 3215.65,
          RUB: 235786.69,
          EUR: 2741.52,
        },
      },
    ],
}

let deepData = {};

response.data.forEach(obj => { deepData = deepMerge(obj, deepData); })

Exploring the intricacies of nested objects

Answer №1

Answer №2

Answer №3

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