Exploring the for... in loop for iteration in JavaScript

Question

Exploring the for... in loop for iteration in JavaScript

I am facing an issue with populating an empty array named objToArray using a for-in-loop. The goal is to fill the array with numbers from a hash object checkObj, but only if the keys have values that are greater than or equal to 2.

const checkObj = {
  oddNum: 1,
  evenNum: 2,
  foundNum: 5,
  randomNum: 18
};

const objToArray = [];

for (let values in checkObj) {
  if (Object.values(checkObj) >= 2 ) {
    objToArray.push(checkObj.values())
    }
}

console.log(objToArray);

Despite expecting three elements, [2, 5, 18], my current output is an empty array when logging objToArray.

javascript for-in-loop

Answer 1

Answer №1

Consider using

Object.values(checkObj).filter(x => x >= 2);

.

Retrieve an array of all values using Object.values(checkObj).
Filter the array to get values greater than or equal to 2 with .filter(x => x >= 2).

If you prefer to utilize a for ... in loop, it loops through the object keys allowing access to values through obj[key]. In your case, by declaring for (let values in checkObj), the variable values holds the key to each value in checkObj. Therefore, you can retrieve the value using checkObj[values].

See the output below.

const checkObj = {
  oddNum: 1,
  evenNum: 2,
  foundNum: 5,
  randomNum: 18
};

// Approach 1
let result = Object.values(checkObj).filter(x => x >= 2);
console.log(result);

// Approach 2
const objToArray = [];
for (let values in checkObj) {
  if (checkObj[values] >= 2) {
    objToArray.push(checkObj[values]);
  }
}
console.log(objToArray);

Answer 2

Consider using

Object.values(checkObj).filter(x => x >= 2);

.

Retrieve an array of all values using Object.values(checkObj).
Filter the array to get values greater than or equal to 2 with .filter(x => x >= 2).

If you prefer to utilize a for ... in loop, it loops through the object keys allowing access to values through obj[key]. In your case, by declaring for (let values in checkObj), the variable values holds the key to each value in checkObj. Therefore, you can retrieve the value using checkObj[values].

See the output below.

const checkObj = {
  oddNum: 1,
  evenNum: 2,
  foundNum: 5,
  randomNum: 18
};

// Approach 1
let result = Object.values(checkObj).filter(x => x >= 2);
console.log(result);

// Approach 2
const objToArray = [];
for (let values in checkObj) {
  if (checkObj[values] >= 2) {
    objToArray.push(checkObj[values]);
  }
}
console.log(objToArray);

Answer 3

Answer №2

Is this what you were looking for?

The for...in loop goes through all the keys of an object, not the values.

const checkObjects = {
  evenNumber: 2,
  oddNumber: 3,
  primeNumber: 7,
  randomNum: 20
};

const objectsToArray = [];

for (let keyValue in checkObjects) {
  if (checkObjects[keyValue] >= 3) {
    objectsToArray.push(checkObjects[keyValue])
  }
}

console.log(objectsToArray)

Answer 4

Is this what you were looking for?

The for...in loop goes through all the keys of an object, not the values.

const checkObjects = {
  evenNumber: 2,
  oddNumber: 3,
  primeNumber: 7,
  randomNum: 20
};

const objectsToArray = [];

for (let keyValue in checkObjects) {
  if (checkObjects[keyValue] >= 3) {
    objectsToArray.push(checkObjects[keyValue])
  }
}

console.log(objectsToArray)

Answer 5

Answer №3

Give this a try:

const sampleObject = {
    firstNumber: 3,
    secondNumber: 6,
    thirdNumber: 9,
    fourthNumber: 12
};
    
const objectValuesArray = [];

for (let [key, value] of Object.entries(sampleObject)) {
    if(value>=6){
        objectValuesArray.push(value);
    }
}

console.log(objectValuesArray);

Answer 6

Give this a try:

const sampleObject = {
    firstNumber: 3,
    secondNumber: 6,
    thirdNumber: 9,
    fourthNumber: 12
};
    
const objectValuesArray = [];

for (let [key, value] of Object.entries(sampleObject)) {
    if(value>=6){
        objectValuesArray.push(value);
    }
}

console.log(objectValuesArray);

Answer 7

Answer №4

Give this a shot

const testObject = {
  first: "apple",
  second: "banana",
  third: "carrot",
  fourth: "date"
};

let objectArray = [];
objectArray = Object.values(testObject).filter(item => item.length > 5);
console.log(objectArray);

Answer 8

Give this a shot

const testObject = {
  first: "apple",
  second: "banana",
  third: "carrot",
  fourth: "date"
};

let objectArray = [];
objectArray = Object.values(testObject).filter(item => item.length > 5);
console.log(objectArray);

Answer 9

Answer №5

Give this a shot: Hopefully you understood it ..

const testObject = {
  firstNum: 3,
  secondNum: 6,
  thirdNum: 9,
  fourthNum: 12
};

let objectArray = [];

for (let val of Object.values(testObject)) {
  console.log(val);
  if (val >= 6) {
    objectArray.push(val);
  }
}

Answer 10

Give this a shot: Hopefully you understood it ..

const testObject = {
  firstNum: 3,
  secondNum: 6,
  thirdNum: 9,
  fourthNum: 12
};

let objectArray = [];

for (let val of Object.values(testObject)) {
  console.log(val);
  if (val >= 6) {
    objectArray.push(val);
  }
}

Answer 11

Answer №6

let numbers = {
  first: 11,
  second: 22,
  third: 33,
  fourth: 44
};

let numArray = []; 

//converting the for loop to a forEach loop that cycles through the keys
Object.keys(numbers).forEach((key) => {
  if (numbers[key]) {
    numArray.push(numbers[key])
  }
})

Answer 12

let numbers = {
  first: 11,
  second: 22,
  third: 33,
  fourth: 44
};

let numArray = []; 

//converting the for loop to a forEach loop that cycles through the keys
Object.keys(numbers).forEach((key) => {
  if (numbers[key]) {
    numArray.push(numbers[key])
  }
})

Exploring the for... in loop for iteration in JavaScript

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

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