Exploring the difference between reversing elements into a new array versus reversing them in

Recently, I've been experimenting with two methods to reverse an array. Firstly, I tried using the push method to create a new array. Secondly, I attempted using destructuring to mutate the original array.

I'm curious about which of these techniques is more efficient in terms of speed, and wondering why that might be the case.

Answer №1

If your code is well-optimized:

  • The first choice has a space complexity of O(n^2), while the second option has a space complexity of O(n+1).
  • When it comes to time complexity, the first choice has O(n), whereas the second option has O(n/2).

It's worth mentioning that you can also utilize the built-in method Array.prototype.reverse() for this task.

Answer №2

When referring to the push helper method for creating a new array by looping through the provided array, the entire array must be traversed in order to reverse it. This results in a time complexity of O(n). Similarly, reversing an array in place also has a time complexity of O(n), even though only half of the array needs to be traversed. The reason for this is that O(n/2) can be simplified to O(n), ultimately resulting in the same time complexity. Therefore, while reversing in place technically takes less time, the overall time complexity remains unchanged.

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