Exploring all possible combinations in JavaScript, including both individual and dual combinations

Question

Exploring all possible combinations in JavaScript, including both individual and dual combinations

I have a collection of objects and I am in search of various combinations for them. The code I currently have is able to find all the combinations, but it only calculates the number of combinations based on the length of the input array.

For instance, using the provided array with the function below results in 27 potential combinations. However, these combinations do not include single elements or pairs.

[
[{ optionName: "red" },{ optionName: "blue"  },{ optionName: "green" }],
[{ optionName: "S" },{ optionName: "L" },{ optionName: "XL" }],
[{ optionName: "spotted" },{ optionName: "striped" },{ optionName: "lined" }],
]

Here are some examples of the combinations:

[{ optionName: "red" },{ optionName: "L"  },{ optionName: "spotted" }]
[{ optionName: "red" },{ optionName: "S"  },{ optionName: "spotted" }]
[{ optionName: "red" },{ optionName: "S"  },{ optionName: "lined" }]

However, I also want to generate combinations like:

[{ optionName: "red" }]
[{ optionName: "red" },{ optionName: "S"  }]
[{ optionName: "red" },{ optionName: "L"  }]

This is the current code implementation:

var r = [],
    arg = arrayOfObjects,
    max = arg.length - 1;
function helper(arr, i) {
    for (var j = 0, l = arg[i].length; j < l; j++) {
        var a = arr.slice(0);
        a.push(arg[i][j]);
        if (i == max) r.push(a);
        else helper(a, i + 1);
    }
}
helper([], 0);

Is there a way to identify all combinations, including individual and paired options?

javascript arrays

Answer 1

Answer №1

To enhance each inner array, consider inserting a placeholder like undefined, create a cartesian product, filter out arrays containing undefined, and remove the initial empty array.

var data = [[{ optionName: "red" }, { optionName: "blue" }, { optionName: "green" }], [{ optionName: "S" }, { optionName: "L" }, { optionName: "XL" }], [{ optionName: "spotted" }, { optionName: "striped" }, { optionName: "lined" }]], 
    result = data
        .map(a => [undefined, ...a])
        .reduce((a, b) => a.reduce((r, v) => r.concat(b.map(w => [].concat(v, w))), []))
        .map(a => a.filter(Boolean))
        .slice(1);

console.log(result.length);
document.getElementById('out').innerHTML = JSON.stringify(result, null, 4);

<pre id="out"><pre>

Answer 2

To enhance each inner array, consider inserting a placeholder like undefined, create a cartesian product, filter out arrays containing undefined, and remove the initial empty array.

var data = [[{ optionName: "red" }, { optionName: "blue" }, { optionName: "green" }], [{ optionName: "S" }, { optionName: "L" }, { optionName: "XL" }], [{ optionName: "spotted" }, { optionName: "striped" }, { optionName: "lined" }]], 
    result = data
        .map(a => [undefined, ...a])
        .reduce((a, b) => a.reduce((r, v) => r.concat(b.map(w => [].concat(v, w))), []))
        .map(a => a.filter(Boolean))
        .slice(1);

console.log(result.length);
document.getElementById('out').innerHTML = JSON.stringify(result, null, 4);

<pre id="out"><pre>

Answer 3

Answer №2

An efficient and straightforward approach: To solve this problem, you will need to loop through the array of arrays and identify all potential outcomes.

const addToEach = (element, arr) => [...arr, element];

const getAllPossibilitiesForSingleArray = (arr) => {
  let result = [];
  for(let i=0;i<arr.length;i++) {
    const combinationsWithNewElement = result.map(ar => addToEach(arr[i], ar))
    result.push(...combinationsWithNewElement, [arr[i]]);
  }
 return result;
};


const getAllPossibilitiesForArrays = arrays => arrays.map(getAllPossibilitiesForSingleArray);

To determine all possibilities within a single array, I have iterated through each element in the array, adding it to the existing result array along with all previous combinations.

You can also achieve this using pure functions (which is often preferred):

const getAllPossibilitiesForSingleArrayFunc = (arr) =>
  arr.reduce((acc, curr, i) => {
    const combinationsWithNewElement = acc.map(ar => addToEach(arr[i], ar))
    return [...acc, [arr[i]], ...combinationsWithNewElement]
  },[]);

const getAllPossibilitiesForArraysFunc = arrays => arrays.map(getAllPossibilitiesForSingleArrayFunc);

Answer 4

An efficient and straightforward approach: To solve this problem, you will need to loop through the array of arrays and identify all potential outcomes.

const addToEach = (element, arr) => [...arr, element];

const getAllPossibilitiesForSingleArray = (arr) => {
  let result = [];
  for(let i=0;i<arr.length;i++) {
    const combinationsWithNewElement = result.map(ar => addToEach(arr[i], ar))
    result.push(...combinationsWithNewElement, [arr[i]]);
  }
 return result;
};


const getAllPossibilitiesForArrays = arrays => arrays.map(getAllPossibilitiesForSingleArray);

To determine all possibilities within a single array, I have iterated through each element in the array, adding it to the existing result array along with all previous combinations.

You can also achieve this using pure functions (which is often preferred):

const getAllPossibilitiesForSingleArrayFunc = (arr) =>
  arr.reduce((acc, curr, i) => {
    const combinationsWithNewElement = acc.map(ar => addToEach(arr[i], ar))
    return [...acc, [arr[i]], ...combinationsWithNewElement]
  },[]);

const getAllPossibilitiesForArraysFunc = arrays => arrays.map(getAllPossibilitiesForSingleArrayFunc);

Exploring all possible combinations in JavaScript, including both individual and dual combinations

Answer №1

Answer №2

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