Experiencing a problem with a loop structure in my code

Question

Experiencing a problem with a loop structure in my code

I've been trying to create a loop that will increase the temperature by 10 degrees every 2 minutes. However, I'm struggling to figure out how to stop the temperature at 120 degrees after 16 minutes. Any suggestions on how to solve this issue?

var temp = 30,
    min = 0;
console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 25; min++) {

   if (min % 2 === 0) {
       temp += 10;
       console.log("Minutes passed: " + min + 
                    ", we are cooking at " + temp + " deg");
   }

   if (min % 2 !== 0 && min === 25) {
       console.log("Total minutes of cooking is 25 min");
   }
}

The expected output should be as follows:

Cooking started at 30 deg
Minutes passed: 0, we are cooking at 40 deg
Minutes passed: 2, we are cooking at 50 deg
Minutes passed: 4, we are cooking at 60 deg
Minutes passed: 6, we are cooking at 70 deg
Minutes passed: 8, we are cooking at 80 deg
Minutes passed: 10, we are cooking at 90 deg
Minutes passed: 12, we are cooking at 100 deg
Minutes passed: 14, we are cooking at 110 deg
Minutes passed: 16, we are cooking at 120 deg
Minutes passed: 18, we are cooking at 120 deg
Minutes passed: 20, we are cooking at 120 deg
Minutes passed: 22, we are cooking at 120 deg
Minutes passed: 24, we are cooking at 120 deg
Total minutes of cooking is 25 min

javascript loops for-loop

Answer 1

Answer №1

To simplify the code, you can use a formula for temp in relation to min. By utilizing Math.min, you can ensure that the temperature doesn't go beyond a certain value. Since you only need to display something every two minutes, consider adjusting your loop accordingly. Additionally, since the 25-minute message is only displayed once at the end, it can be placed outside of the loop:

console.log("Cooking started at 30 deg");
for (var min = 0; min <= 25; min+=2) {
   var temp = Math.min(120, 40 + min*5);
   console.log("Minutes passed: " + min + ", we are cooking at " + temp + " deg");
}
console.log("Total minutes of cooking is 25 min");

Answer 2

To simplify the code, you can use a formula for temp in relation to min. By utilizing Math.min, you can ensure that the temperature doesn't go beyond a certain value. Since you only need to display something every two minutes, consider adjusting your loop accordingly. Additionally, since the 25-minute message is only displayed once at the end, it can be placed outside of the loop:

console.log("Cooking started at 30 deg");
for (var min = 0; min <= 25; min+=2) {
   var temp = Math.min(120, 40 + min*5);
   console.log("Minutes passed: " + min + ", we are cooking at " + temp + " deg");
}
console.log("Total minutes of cooking is 25 min");

Answer 3

Answer №2

It's curious that you would continue looping even after reaching the maximum value you know. One simple solution is to limit the loop count to <=16 since you are aware that the process should end there.

var temp = 30,
    min = 0;
    console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 16; min++) {

   if (min % 2 === 0) {
       temp += 10;
       console.log("Minutes passed: " + min + 
                    ", we are cooking at " + temp + " deg");
   }

   if (min % 2 !== 0 && min === 16) {
       console.log("Total minutes of cooking is 25 min");
   }
}

Alternatively, if you must reach 25 minutes, you can add a condition for 16 minutes and adjust the temperature temp accordingly:

var temp = 30,
    min = 0;
    console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 25; min++) {

   if(min >= 16) {
      // If we've reached this point, at least 16 minutes of cooking have passed
      temp = 120;  // Set temp to maximum
      console.log("Minutes passed: " + min + ", we are cooking at " + temp + " deg");
   } else if (min % 2 === 0) {
       // If we've arrived here, it means we're less than 16 minutes in and on an even minute, so proceed as usual
       temp += 10;
       console.log("Minutes passed: " + min + ", we are cooking at " + temp + " deg");
   }

   if (min % 2 !== 0 && min === 25) {
       console.log("Total minutes of cooking is 25 min");
   }
}

Answer 4

It's curious that you would continue looping even after reaching the maximum value you know. One simple solution is to limit the loop count to <=16 since you are aware that the process should end there.

var temp = 30,
    min = 0;
    console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 16; min++) {

   if (min % 2 === 0) {
       temp += 10;
       console.log("Minutes passed: " + min + 
                    ", we are cooking at " + temp + " deg");
   }

   if (min % 2 !== 0 && min === 16) {
       console.log("Total minutes of cooking is 25 min");
   }
}

Alternatively, if you must reach 25 minutes, you can add a condition for 16 minutes and adjust the temperature temp accordingly:

var temp = 30,
    min = 0;
    console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 25; min++) {

   if(min >= 16) {
      // If we've reached this point, at least 16 minutes of cooking have passed
      temp = 120;  // Set temp to maximum
      console.log("Minutes passed: " + min + ", we are cooking at " + temp + " deg");
   } else if (min % 2 === 0) {
       // If we've arrived here, it means we're less than 16 minutes in and on an even minute, so proceed as usual
       temp += 10;
       console.log("Minutes passed: " + min + ", we are cooking at " + temp + " deg");
   }

   if (min % 2 !== 0 && min === 25) {
       console.log("Total minutes of cooking is 25 min");
   }
}

Answer 5

Answer №3

To ensure optimal cooking, implement a condition that checks if the elapsed time exceeds 16 minutes and then adjusts the temperature to 120 degrees. If not, increase the temperature by 5 degrees:

var temp = 30,
min = 0;
console.log("Initiating cooking at " + temp + " degrees");

for (min = 0; min <= 25; min++) {

   if (min >= 16) {
       temp = 120;
   } else {
       temp += 5;
   }

   if (min % 2 === 0) {
       console.log("Minutes passed: " + min + 
                    ", current temperature: " + temp + " degrees");
   }

   if (min % 2 !== 0 && min === 25) {
       console.log("Total cook time: 25 minutes");
   }
}

It's advisable to segregate tasks like logging and temperature adjustments into distinct code blocks for clarity.

Answer 6

To ensure optimal cooking, implement a condition that checks if the elapsed time exceeds 16 minutes and then adjusts the temperature to 120 degrees. If not, increase the temperature by 5 degrees:

var temp = 30,
min = 0;
console.log("Initiating cooking at " + temp + " degrees");

for (min = 0; min <= 25; min++) {

   if (min >= 16) {
       temp = 120;
   } else {
       temp += 5;
   }

   if (min % 2 === 0) {
       console.log("Minutes passed: " + min + 
                    ", current temperature: " + temp + " degrees");
   }

   if (min % 2 !== 0 && min === 25) {
       console.log("Total cook time: 25 minutes");
   }
}

It's advisable to segregate tasks like logging and temperature adjustments into distinct code blocks for clarity.

Answer 7

Answer №4

It seems like you're looking to halt the modifications on temp once it hits 120. You can achieve this using either the break; or continue; statements.

The break; statement will completely terminate the for loop, ending the iteration when it's called.

On the other hand, the continue; statement will simply bypass the remaining code within that specific iteration of the loop. If you wish to continue with the rest of the loop even after reaching 120, then this is the suitable choice. Here's an example:

var temp = 30,
min = 0;
console.log("Cooking started at " + temp + " degrees");

for (min = 0; min <= 25; min++) {

  if(temp >= 120) {
    continue;
    // or 'break;' if you want to exit the entire loop.
  }

  if (min % 2 === 0) {
      temp += 10;
      console.log("Minutes passed: " + min + 
                ", cooking temperature: " + temp + " degrees");
  }

  if (min % 2 !== 0 && min === 25) {
      console.log("Total cooking time is 25 minutes");
  }
}

This code snippet hasn't been thoroughly tested, but it demonstrates the concept.

Answer 8

It seems like you're looking to halt the modifications on temp once it hits 120. You can achieve this using either the break; or continue; statements.

The break; statement will completely terminate the for loop, ending the iteration when it's called.

On the other hand, the continue; statement will simply bypass the remaining code within that specific iteration of the loop. If you wish to continue with the rest of the loop even after reaching 120, then this is the suitable choice. Here's an example:

var temp = 30,
min = 0;
console.log("Cooking started at " + temp + " degrees");

for (min = 0; min <= 25; min++) {

  if(temp >= 120) {
    continue;
    // or 'break;' if you want to exit the entire loop.
  }

  if (min % 2 === 0) {
      temp += 10;
      console.log("Minutes passed: " + min + 
                ", cooking temperature: " + temp + " degrees");
  }

  if (min % 2 !== 0 && min === 25) {
      console.log("Total cooking time is 25 minutes");
  }
}

This code snippet hasn't been thoroughly tested, but it demonstrates the concept.

Answer 9

Answer №5

After verifying the value of the variable temp, you can use the break statement to exit the loop.

console.clear();
var temp = 30,
  min = 0;
console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 25; min++) {
  if (temp >= 120) {
    break;
  }

  if (min % 2 === 0) {
    temp += 10;
    console.log("Minutes passed: " + min +
      ", we are cooking at " + temp + " deg");
  }

  if (min % 2 !== 0 && min === 25) {
    console.log("Total minutes of cooking is 25 min");
  }
}

Answer 10

After verifying the value of the variable temp, you can use the break statement to exit the loop.

console.clear();
var temp = 30,
  min = 0;
console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 25; min++) {
  if (temp >= 120) {
    break;
  }

  if (min % 2 === 0) {
    temp += 10;
    console.log("Minutes passed: " + min +
      ", we are cooking at " + temp + " deg");
  }

  if (min % 2 !== 0 && min === 25) {
    console.log("Total minutes of cooking is 25 min");
  }
}

Answer 11

Answer №6

If you want to condense your code, try using a ternary operator inside the console.log():

var temperature = 30,
    minutes = 0;
    console.log("Cooking started at " + temperature + " deg");

for (minutes = 0; minutes <= 25; minutes++) {
   if (minutes % 2 === 0) {
       temperature += 10;
       console.log("Minutes passed: " + minutes + 
                    ", we are cooking at " + (temperature>120?120:temperature) + " deg");
   }

   if (minutes % 2 !== 0 && minutes === 25) {
       console.log("Total minutes of cooking is 25 min");
   }
}

Here's what the shorthand notation means:

(temperature>120?120:temperature)
// equivalent to
if (temperature>120) { 120 } else { temperature }

Answer 12

If you want to condense your code, try using a ternary operator inside the console.log():

var temperature = 30,
    minutes = 0;
    console.log("Cooking started at " + temperature + " deg");

for (minutes = 0; minutes <= 25; minutes++) {
   if (minutes % 2 === 0) {
       temperature += 10;
       console.log("Minutes passed: " + minutes + 
                    ", we are cooking at " + (temperature>120?120:temperature) + " deg");
   }

   if (minutes % 2 !== 0 && minutes === 25) {
       console.log("Total minutes of cooking is 25 min");
   }
}

Here's what the shorthand notation means:

(temperature>120?120:temperature)
// equivalent to
if (temperature>120) { 120 } else { temperature }

Experiencing a problem with a loop structure in my code

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

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