Executing a function stored in an array using JavaScript

While practicing JavaScript, I came across a sample code where I tried to call a function from an array. However, the output returned undefined along with the expected result from the function. I'm confused as to why this is happening, especially since I've correctly called the index of the array containing the function. Can someone help me understand what's going on?

const arr = [
    "test1",
    "test2",
    function(){console.log("hi")}
];

console.log(arr[2]());

Output:

Babel Compiler v6.4.4
Copyright (c) 2014-2015 Sebastian McKenzie
   
hi
undefined
=> undefined

Answer №1

By nature, the function logs "hello" without returning anything. When using console.log(arr2), it will output the return value as undefined.

To achieve what you intended, consider a function structured like this:

function() {return "hello"} 

Answer №2

Hello there, to execute the function at index 2 in the array 'arr', simply write arr[2]() as shown below:

const arr = [
        "test1",
        "test2",
        function(){console.log("hi")}
    ];

arr[2]();

Answer №3

When you call the function inside a console.log statement, it means you are displaying the return value of that function.

To understand this concept better, take a look at the following example where we add the return values to explain:

const arr = [
    "test1",
    "test2",
    function(){console.log("hi")},
    function(){console.log("hello"); return "world"}
];

console.log('1. The return value of the function is: ', arr[2]());
console.log('2. The return value of the function is: ', arr[3]());

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