Exclude a variety of keys using wildcards or regex when conducting comparisons

Question

Exclude a variety of keys using wildcards or regex when conducting comparisons

How can I exclude certain properties in a JSON object that contain specific characters?

var obj1 = {name: "James", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""}
var obj2 = {name: "Maria", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""}

Now, I want to remove all properties that contain the string foo.

var result = _.isEqual(
  _.omit(obj1, ['\*foo\*']),
  _.omit(obj2, ['\*foo\*'])
);

Is there a way to achieve this? Any suggestions would be appreciated.

javascript json underscore.js

Answer 1

Answer №1

When working with vanilla JS, there are various approaches you can take to achieve a certain result.

One technique involves filtering keys that contain specific values like 'foo'; then extracting the key-value pairs from the original array based on these filtered keys; finally, combining them into a final object.

Filter out keys containing 'foo' using the Object.keys() method
Map over the filtered keys to create an array of objects with the key-value pairs
Combine the objects using Object.assign() to form a new object

var obj1 = {name: "James", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""}
var obj2 = {name: "Maria", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""};

var o = Object.keys(obj1).filter(o=> !o.includes('foo')),
    i = o.map(i=> ({[i] : obj1[i]})),
    obj =  Object.assign({}, ...i);
    console.log(obj)

Answer 2

When working with vanilla JS, there are various approaches you can take to achieve a certain result.

One technique involves filtering keys that contain specific values like 'foo'; then extracting the key-value pairs from the original array based on these filtered keys; finally, combining them into a final object.

Filter out keys containing 'foo' using the Object.keys() method
Map over the filtered keys to create an array of objects with the key-value pairs
Combine the objects using Object.assign() to form a new object

var obj1 = {name: "James", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""}
var obj2 = {name: "Maria", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""};

var o = Object.keys(obj1).filter(o=> !o.includes('foo')),
    i = o.map(i=> ({[i] : obj1[i]})),
    obj =  Object.assign({}, ...i);
    console.log(obj)

Answer 3

Answer №2

To exclude certain keys, you can provide a function as an argument to omit method with the key as the second parameter:

const updatedObject = _.omit(originalObject, (value, key) => key.includes('bar'))

Answer 4

To exclude certain keys, you can provide a function as an argument to omit method with the key as the second parameter:

const updatedObject = _.omit(originalObject, (value, key) => key.includes('bar'))

Answer 5

Answer №3

Here is a method you can use to manipulate an object:

function removeProps (obj, prop) {
  Object.keys(obj).forEach((key) => {
    if(key.indexOf(prop) !== -1) delete obj[key];
  });
}
var obj1 = {name: "James", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""};

removeProps(obj1, "foo");
console.log(obj1);

If you want to keep the original object intact, you can do this:

function removeProps (obj, prop) {
  obj = JSON.parse(JSON.stringify(obj));
  Object.keys(obj).forEach((key) => {
    if(key.indexOf(prop) !== -1) delete obj[key];
  });
  return obj;
}
var obj1 = {name: "James", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""};

var obj1Updated = removeProps(obj1, "foo");
console.log(obj1);
console.log(obj1Updated);

Answer 6

Here is a method you can use to manipulate an object:

function removeProps (obj, prop) {
  Object.keys(obj).forEach((key) => {
    if(key.indexOf(prop) !== -1) delete obj[key];
  });
}
var obj1 = {name: "James", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""};

removeProps(obj1, "foo");
console.log(obj1);

If you want to keep the original object intact, you can do this:

function removeProps (obj, prop) {
  obj = JSON.parse(JSON.stringify(obj));
  Object.keys(obj).forEach((key) => {
    if(key.indexOf(prop) !== -1) delete obj[key];
  });
  return obj;
}
var obj1 = {name: "James", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""};

var obj1Updated = removeProps(obj1, "foo");
console.log(obj1);
console.log(obj1Updated);

Answer 7

Answer №4

In response to your request for a solution using regex, here is the code snippet:

const person1 = {name: "James", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""}
const person2 = {name: "Maria", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""};

Object.prototype.filterRegex = function(regex) {
    let filteredKeys = Object.keys(this).filter((key) => !regex.test(key));
    return filteredKeys.reduce((result, key) => {
        result[key] = this[key];
        return result;
    }, {});
};

person1.filterRegex(/foo/);
person2.filterRegex(/foo/);

Answer 8

In response to your request for a solution using regex, here is the code snippet:

const person1 = {name: "James", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""}
const person2 = {name: "Maria", age: 17, creation: "13-02-2016", deletion: "13-04-2016", foo_x:"", foo_y:"", foo_z:""};

Object.prototype.filterRegex = function(regex) {
    let filteredKeys = Object.keys(this).filter((key) => !regex.test(key));
    return filteredKeys.reduce((result, key) => {
        result[key] = this[key];
        return result;
    }, {});
};

person1.filterRegex(/foo/);
person2.filterRegex(/foo/);

Exclude a variety of keys using wildcards or regex when conducting comparisons

Answer №1

Answer №2

Answer №3

Answer №4

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