Is there a way to loop through an array and check if each word is a palindrome, instead of manually passing an argument for each word? If a word is a palindrome, return the word; otherwise, return 0.
var myArray = ['viicc', 'cecarar', 'honda'];
function palindromize(words) {
var p = words.split("").reverse().join("");
if(p === words){
return(words);
} else {
return("0");
}
}
palindromize("viicc");
palindromize("cecarar");
palindromize("honda");
The best approach is to utilize a for loop.
for (let index = 0; index < arrayLength; index++) {
executeFunction(myArray[index]);
}
I would recommend mastering them thoroughly, as they are widely considered the most frequently used type of looping structure.
Utilize the power of Array.prototype.map():
The
map()function generates a new array by applying a given function to each element in the original array.
myArray.map(palindromize)
var myArray = ['viicc', 'cecarar', 'honda', 'ada'];
function palindromize(word) {
var p = word.split("").reverse().join("");
return p === word ? word : 0;
}
document.write('<pre>' + JSON.stringify(myArray.map(palindromize), 0, 4) + '</pre>');let words = ['hello', 'world', 'level', 'radar' ];
let palindromes = words.filter(function(word,index,array){
let reverseWord = word.split('').reverse().join('');
if(word === reverseWord){
console.log( array[index] +" " + " is a palindrome" );
}
});
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