examine and contrast two arrays

Question

examine and contrast two arrays

function checkArray(arr) {
  //target array to check against
  const targetArray = [
    [0, 1, 2],
    [3, 4, 5],
    [6, 7, 8],
    [0, 3, 6],
    [1, 4, 7],
    [2, 5, 8],
    [0, 4, 8],
    [2, 4, 6],
  ]

  for (let i = 0; i < targetArray.length; i++) {
    compareArrays(arr, targetArray[i])
  }
}

function compareArrays(supplied, subArray) {
  supplied.sort()
  subArray.sort()
  let i = 0
  let j = 0
  for (i, j; i < supplied.length && j < subArray.length;) {
    if (supplied[i] < subArray[j]) {
      ++i
    } else if (supplied[i] == subArray[j]) {
      ++i, ++j
    } else {
      return false
    }
  }
  return j == subArray.length;
}


checkArray([1, 3, 7, 4])

I'm attempting to create a function that checks if every element in an array is present in any of the nested arrays within the object.

I referred to a function from this post, but I am puzzled as to why I am receiving undefined output instead of true.

javascript arrays

Answer 1

Answer №1

If you are looking to determine if any combination of numbers from the winningIds array is present in the arr array, here is a sample code implementation:

function findWinningCombo(arr) {
  // Array containing winning combinations
  const winningIds = [
    [0, 1, 2],
    [3, 4, 5],
    [6, 7, 8],
    [0, 3, 6],
    [1, 4, 7],
    [2, 5, 8],
    [0, 4, 8],
    [2, 4, 6],
  ]

  var hasWinner = false;

  for (let i = 0; i < winningIds.length && !hasWinner; i++) {
     hasWinner = checkCombination(arr, winningIds[i])
  }

  return hasWinner;
}

function checkCombination(mainArray, subArray) {
  mainArray.sort()
  subArray.sort()

  for (var i = 0; i < subArray.length; i++) {
    if (mainArray.indexOf(subArray[i]) == -1) {
        return false;
    }
  }
  return true;
}

findWinningCombo([1, 3, 7, 4]);

Answer 2

If you are looking to determine if any combination of numbers from the winningIds array is present in the arr array, here is a sample code implementation:

function findWinningCombo(arr) {
  // Array containing winning combinations
  const winningIds = [
    [0, 1, 2],
    [3, 4, 5],
    [6, 7, 8],
    [0, 3, 6],
    [1, 4, 7],
    [2, 5, 8],
    [0, 4, 8],
    [2, 4, 6],
  ]

  var hasWinner = false;

  for (let i = 0; i < winningIds.length && !hasWinner; i++) {
     hasWinner = checkCombination(arr, winningIds[i])
  }

  return hasWinner;
}

function checkCombination(mainArray, subArray) {
  mainArray.sort()
  subArray.sort()

  for (var i = 0; i < subArray.length; i++) {
    if (mainArray.indexOf(subArray[i]) == -1) {
        return false;
    }
  }
  return true;
}

findWinningCombo([1, 3, 7, 4]);

examine and contrast two arrays

Answer №1

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