Evaluating numerous array elements within an if statement

Question

Evaluating numerous array elements within an if statement

For my simple tic tac toe game, I am currently checking for various win states. The game board is stored in an array, and to check for a win with the top three spaces, I am using the following logic:

if (tableArr[0].hasClass('userTaken') && tableArr[1].hasClass('userTaken') && tableArr[2].hasClass('userTaken')){
    select(); //ends game
}

I am trying to find a way to condense this code. I attempted

tableArr[0,1,2].hasClass('userTaken')

but it did not work. Any advice on how to optimize this further?

javascript arrays

Answer 1

Answer №1

To achieve this, you can consider utilizing the every method, along with slicing the array. Here's an example of how you can do this:

tableArr.slice(0, 3).every(x => x.hasClass('userTaken'))

In this code snippet, we are taking the first three elements of the array using the slice method, and then checking if the test passes for each element with the every method.

If you are working on a tic-tac-toe game, you may also need to check diagonals, which can be a bit more complex when using .slice. In such cases, you can utilize map as well. Here's how you can do it:

[0,1,2].map(idx => tableArr[idx]).every(x => x.hasClass('userTaken'))

Answer 2

To achieve this, you can consider utilizing the every method, along with slicing the array. Here's an example of how you can do this:

tableArr.slice(0, 3).every(x => x.hasClass('userTaken'))

In this code snippet, we are taking the first three elements of the array using the slice method, and then checking if the test passes for each element with the every method.

If you are working on a tic-tac-toe game, you may also need to check diagonals, which can be a bit more complex when using .slice. In such cases, you can utilize map as well. Here's how you can do it:

[0,1,2].map(idx => tableArr[idx]).every(x => x.hasClass('userTaken'))

Answer 3

Answer №2

If you want to verify whether an element lacks a specific class, you can use the some method like this:

tableArr.slice(0, 3).some(x => !x.hasClass('userTaken'))

Answer 4

If you want to verify whether an element lacks a specific class, you can use the some method like this:

tableArr.slice(0, 3).some(x => !x.hasClass('userTaken'))

Evaluating numerous array elements within an if statement

Answer №1

Answer №2

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