Contained within the quickSort function is the following code:
if (leftArr.length > 0 && rightArr.length > 0 ){
return [...quickSort(leftArr) , pivot , ...quickSort(rightArr)];
}else if (leftArr.length > 0){
return [...quickSort(leftArr) , pivot];
}else {
return [pivot ,...quickSort(rightArr)];
};
This code block indicates the following:
- If there are elements both to the left and right, then sort both sides
- Otherwise, if there are elements only to the left, then sort the left side
- Otherwise, sort the right side
The issue lies in not accounting for the scenario where both leftArr and rightArr have a length less than or equal to 0. This needs to be handled as well.
The revised code snippet below attempts to address this problem by adding one condition. It may not fully resolve all issues with your initial implementation, but it addresses the logical flaw mentioned above:
//calculate pivot
if (leftArr.length > 0 && rightArr.length > 0 ){
return [...quickSort(leftArr) , pivot , ...quickSort(rightArr)];
}else if (leftArr.length > 0){
return [...quickSort(leftArr) , pivot];
}else if (rightArr.length > 0){
return [pivot ,...quickSort(rightArr)];
}else {
return pivot;
};
A comment is included indicating that calculating the pivot is essential. Various methods can be employed for pivot calculation, as discussed in this article.
Prioritize rectifying the recursive call issue before proceeding further, ensuring the function does not recursively call itself excessively and cause adverse effects on system resources.