Enhancing JavaScript with a versatile Regex to capture diverse patterns

Question

Enhancing JavaScript with a versatile Regex to capture diverse patterns

Here is a regular expression (for base64) that matches every 5 characters in a string:

/[a-zA-Z0-9/+]{5}/g

For example, if the input string is:

"19jZ2uLj5OXm5+jp6vLz9PX29/j5+v/aAAw"

The resulting matches would be:

19jZ2
uLj5O
Xm5+j
p6vLz
9PX29
/j5+v
/aAAw

To achieve a regex pattern for all possible consecutive 5-character matches in the string, you would write:

19jZ2
9jZ2u
jZ2uL
Z2uLj
2uLj5
uLj5O
and so on...

(^This will match literally every possible 5 consecutive characters in the string)

javascript regex string char base64

Answer 1

Answer №1

What do you think of this:

"tLmCOqYOl6fWgoXngQxRrmEpbFgN9TbBPH".split('').map(function(el, ind, array) { 
    return arr.slice(ind,ind+5).join('') }
).slice(0,-4)

Answer 2

What do you think of this:

"tLmCOqYOl6fWgoXngQxRrmEpbFgN9TbBPH".split('').map(function(el, ind, array) { 
    return arr.slice(ind,ind+5).join('') }
).slice(0,-4)

Answer 3

Answer №2

According to the feedback from adeneo:

var result = [],
    s = '19jZ2uLj5OXm5+jp6vLz9PX29/j5+v/aAAw';
while (s.length > 4) {
    result.push(s.substr(0, 5));
    s = s.substr(1);
}

Answer 4

According to the feedback from adeneo:

var result = [],
    s = '19jZ2uLj5OXm5+jp6vLz9PX29/j5+v/aAAw';
while (s.length > 4) {
    result.push(s.substr(0, 5));
    s = s.substr(1);
}

Answer 5

Answer №3

Check out this idea :

function separate(s) {
    var allowed = /^[a-z\d/+]{5}/i,
        output = [],
        matched;
    while (s.length > 4) {
        matched = s.match(allowed);
        matched && output.push(matched[0]);
        s = s.substr(1); // eliminate first character
    }
    return output;
}

The regular expression captures the first five characters in each iteration :

separate('19jZ2uLj5OXm5+jp6vLz9PX29/j5+v/aAAw'); // ['19jZ2', '9jZ2u', ...]
separate('19jZ2=uLj5OXm5+jp6vLz9PX29/j5+v/aAAw'); // ['19jZ2', 'uLj5O', ...]

Answer 6

Check out this idea :

function separate(s) {
    var allowed = /^[a-z\d/+]{5}/i,
        output = [],
        matched;
    while (s.length > 4) {
        matched = s.match(allowed);
        matched && output.push(matched[0]);
        s = s.substr(1); // eliminate first character
    }
    return output;
}

The regular expression captures the first five characters in each iteration :

separate('19jZ2uLj5OXm5+jp6vLz9PX29/j5+v/aAAw'); // ['19jZ2', '9jZ2u', ...]
separate('19jZ2=uLj5OXm5+jp6vLz9PX29/j5+v/aAAw'); // ['19jZ2', 'uLj5O', ...]

Answer 7

Answer №4

To solve this specific input, a straightforward ([a-zA-Z0-9+\/]{5}) pattern can be used

Check out the live DEMO here

Alternatively, if your string is enclosed in quotes, consider using

(?:"|\G(?<!^))([a-zA-Z0-9+\/]{5}|[a-zA-Z0-9+\/]+)(?=.*?")

Test it with the live DEMO here

Or try

(?:"|\G(?<!^))([a-zA-Z0-9+\/]{5})(?=(?:[a-zA-Z0-9+\/]{5})*")

if your string length is exactly divisible by 5

Explore the live DEMO for this option

Answer 8

To solve this specific input, a straightforward ([a-zA-Z0-9+\/]{5}) pattern can be used

Check out the live DEMO here

Alternatively, if your string is enclosed in quotes, consider using

(?:"|\G(?<!^))([a-zA-Z0-9+\/]{5}|[a-zA-Z0-9+\/]+)(?=.*?")

Test it with the live DEMO here

Or try

(?:"|\G(?<!^))([a-zA-Z0-9+\/]{5})(?=(?:[a-zA-Z0-9+\/]{5})*")

if your string length is exactly divisible by 5

Explore the live DEMO for this option

Enhancing JavaScript with a versatile Regex to capture diverse patterns

Answer №1

Answer №2

Answer №3

Answer №4

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