Encountering an issue when implementing a conditional check within the .map() function utilizing ES6 syntax

I'm struggling to assign only the object that contains an iban value to the list in the code snippet below. I haven't been able to fix this issue on my own and would appreciate some assistance.

  This.ibanList = this.data.map(
        (value, index) => {if(value && value.iban){'id': index, 'text': value.iban}});

The following are the values present inside the data:

 "data": [
        {

            "id": "2c4cc5e8-d24d-11e4-8833-150bbf360367"
        },
        {
            "iban": "DE45765459080",
            "id": "2c4cc8ae-d24d-11e4-8833-150bbf360367"
        },
        {

            "iban": "DE3700333333",
            "id": "8a23995d-10d7-11e5-b819-2c44fd83fb24"
        }
    ]

Answer №1

Two issues:

  1. The shorthand version of an arrow function should only contain an expression on the right side of the =>. Instead, you have an if statement. Furthermore, using parentheses inside an arrow function would not be valid even outside it.

  2. map always requires a return value. You haven't provided one for the "else" condition.

In this scenario, you can utilize the conditional operator; I will set null as the return value for the "else" case:

this.ibanList = this.data.map(
    (value, index)=> (value && value.iban ? {'id': index, 'text': value.iban} : null));

var data = [
  {"id": "2c4cc5e8-d24d-11e4-8833-150bbf360367"},
  {"iban": "DE45765459080", "id": "2c4cc8ae-d24d-11e4-8833-150bbf360367"},
  {"iban": "DE3700333333", "id": "8a23995d-10d7-11e5-b819-2c44fd83fb24"}
];
var ibanList = data.map(
    (value, index)=> (value && value.iban ? {'id': index, 'text': value.iban} : null));
console.log(ibanList);

However, keep in mind that the result will include those null values. If you want only the ones where value && value.iban is true, use filter before mapping:

this.ibanList = this.data
    .filter(value => value && value.iban)
    .map((value, index) => ({'id': index, 'text': value.iban}));

var data = [
  {"id": "2c4cc5e8-d24d-11e4-8833-150bbf360367"},
  {"iban": "DE45765459080", "id": "2c4cc8ae-d24d-11e4-8833-150bbf360367"},
  {"iban": "DE3700333333", "id": "8a23995d-10d7-11e5-b819-2c44fd83fb24"}
];
var ibanList = data
    .filter(value => value && value.iban)
    .map((value, index) => ({'id': index, 'text': value.iban}));
console.log(ibanList);

If you prefer to retain the original values instead of replacing them with indexes when filtering, combine both approaches above by filtering after mapping:

this.ibanList = this.data
    .map((value, index)=> (value && value.iban ? {'id': index, 'text': value.iban} : null))
    .filter(value => value); // Eliminates the nulls

var data = [
  {"id": "2c4cc5e8-d24d-11e4-8833-150bbf360367"},
  {"iban": "DE45765459080", "id": "2c4cc8ae-d24d-11e4-8833-150bbf360367"},
  {"iban": "DE3700333333", "id": "8a23995d-10d7-11e5-b819-2c44fd83fb24"}
];
var ibanList = data
    .map((value, index)=> (value && value.iban ? {'id': index, 'text': value.iban} : null))
    .filter(value => value); // Removes the nulls
console.log(ibanList);


Did you intend to substitute the id values (

"2c4cc5e8-d24d-11e4-8833-150bbf360367"
, etc.) with indexes? If not, replace id: index in the code snippets above with id: value.id.

Answer №2

Give this a shot:

    
let info = [{num:3, message: "hello", code: 'abc'}, {num:4, message: "hi", code: 'def'}, {num:15, message: 30}];
let filteredList = info.filter((item) => item && item.code).map(
        (item, idx) => ({'num': idx, 'message': item.code}));
console.log(filteredList);

Answer №3

In order to achieve the expected outcome with the map function, it is essential to ensure that a value is always returned. One way to accomplish this is by first using the filter method on your list.

this.ibanList = this.data.filter(item => item && item.iban)
     .map((item, idx) => ({id: idx, text: item.iban}));

Answer №4

A more efficient solution is to use a single reduce function instead of combining map and filter, which can achieve the same result in O(n) time.

var data = [{"id": "2c4cc5e8-d24d-11e4-8833-150bbf360367"},{"iban": "DE45765459080","id": "2c4cc8ae-d24d-11e4-8833-150bbf360367"},{"iban": "DE3700333333","id": "8a23995d-10d7-11e5-b819-2c44fd83fb24"}],
ibanList = data.reduce((p,c,i) =>  (c.iban && p.push({"id": i, "text": c.iban}),p),[]);
console.log(ibanList)

Answer №5

Opt for using the filter function over map in this scenario.

this.filteredIbanList = this.data.filter((item, i) => {return item && item.iban});

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