Employ SVG clusters as a sophisticated alternative to bars in D3 graphs

Imagine you have a complex data visualization created using D3. You want to go beyond just basic shapes like rectangles and instead build units with different graphics elements, such as rectangles, triangles, text labels, and background rectangles grouped together.

Typically, you would use

var unit = d3.select('.unit').data(units).enter().append('g')
to create these containers. But how can you add inner content without duplicating items on each data update by simply using unit.append('rect')? It's not ideal to check if an element exists before appending it with
if (!unit.select('.label').size()){//append the element} else {//update existing element}
.

When dealing with multiple elements inside a unit, using all those if..then statements can quickly become messy. Is there a more efficient way to handle situations like this?

Answer №1

If you want to streamline your code, consider moving complex drawings into a separate function.

var shape = d3.selectAll('.shape').data(shapes);

// ENTER
shape.enter().append('g')
    .attr('class', 'shape')
    // ... transformation and other shape-level operations here

// UPDATE
shape.transition().duration()
    .call(drawShape);

// EXIT
shape.exit()
    .remove();

Within the drawShape function, you can structure your code like this:

function drawShape(shapes) {
    shapes.each(function(d) {
        var shape = d3.select(this); // select g.shape
        // DRAW LABEL
        var label = shape.selectAll('text')
            .data([d]); // bind data from the shape to the label

        // enter
        label.enter()
            .append('text');

        // update
        label
            .text(function(d) { return d.label; });

        // exit
        // if hiding labels is needed, consider using something like `.data(d.label.length ? [d] : [])` instead of `.data([d])`
        //label.exit().remove();

        // draw other internal elements of the shape
        // DRAW ARROW
        var arrow = shape.selectAll('.arrow').data([d]);
        // .....
    });
}

For further details with comments included, refer to the JSFiddle link provided: http://jsfiddle.net/fd6o4eey/1/

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