Eliminate values from an array by utilizing either a for loop or a custom filtering function

Question

Eliminate values from an array by utilizing either a for loop or a custom filtering function

I need help with removing specific URLs from an array every time they appear. Here is the list of URLs I want to filter out:

"https://basueUrl.com/Claim"
"https://basueUrl.com/ExplanationOfBenefit"

This is my current array:

Array= [  
        "https://basueUrl.com/Patient"
        "https://basueUrl.com/Organization"
        "https://basueUrl.com/Claim"
        "https://basueUrl.com/Practitioner"
        "https://basueUrl.com/Encounter"
        "https://basueUrl.com/Condition"
        "https://basueUrl.com/Claim"
        "https://basueUrl.com/ExplanationOfBenefit"
        "https://basueUrl.com/Claim"
        "https://basueUrl.com/ExplanationOfBenefit" 
        "https://basueUrl.com/ExplanationOfBenefit"
        ]

First Attempt: I tried using a for loop but it didn't work as expected.

for( var i = 0; i < Array.length; i++){ 
   if ( Array[i] === "https://basueUrl.com/ExplanationOfBenefit" || Array[i] === "https://basueUrl.com/Claim") {
    Array.splice(i, 1);
    i--;
   }
}
console.log(Array);

Second Attempt: I also attempted to create a custom remove method, but it didn't yield the desired results.

function arrayRemove(Array, value) {

   return Array.filter(function(ele){
       return ele != value;
   });
}
var result = arrayRemove(Array,"https://basueUrl.com/ExplanationOfBenefit" || Array[i] === "https://basueUrl.com/Claim");

Any suggestions on how I can successfully filter out these URLs would be greatly appreciated!

javascript arrays function for-loop

Answer 1

Answer №1

When dealing with modifying an array during a loop execution, it can cause issues with the index due to the changing length of the array whenever Array.prototype.splice is called.

The second approach may not yield the expected outcome.

console.log("https://basueUrl.com/ExplanationOfBenefit" & "https://basueUrl.com/Claim"); 
// Need an array instead of a single value, like a number.

To tackle this, utilize the filter and includes functions in the following manner:

let skip = ["https://basueUrl.com/Claim", "https://basueUrl.com/ExplanationOfBenefit"];
let arr = ["https://basueUrl.com/Patient","https://basueUrl.com/Organization","https://basueUrl.com/Claim","https://basueUrl.com/Practitioner","https://basueUrl.com/Encounter","https://basueUrl.com/Condition","https://basueUrl.com/Claim","https://basueUrl.com/ExplanationOfBenefit","https://basueUrl.com/Claim","https://basueUrl.com/ExplanationOfBenefit","https://basueUrl.com/ExplanationOfBenefit"];
let result = arr.filter(url => !skip.includes(url));

console.log(result);

Answer 2

When dealing with modifying an array during a loop execution, it can cause issues with the index due to the changing length of the array whenever Array.prototype.splice is called.

The second approach may not yield the expected outcome.

console.log("https://basueUrl.com/ExplanationOfBenefit" & "https://basueUrl.com/Claim"); 
// Need an array instead of a single value, like a number.

To tackle this, utilize the filter and includes functions in the following manner:

let skip = ["https://basueUrl.com/Claim", "https://basueUrl.com/ExplanationOfBenefit"];
let arr = ["https://basueUrl.com/Patient","https://basueUrl.com/Organization","https://basueUrl.com/Claim","https://basueUrl.com/Practitioner","https://basueUrl.com/Encounter","https://basueUrl.com/Condition","https://basueUrl.com/Claim","https://basueUrl.com/ExplanationOfBenefit","https://basueUrl.com/Claim","https://basueUrl.com/ExplanationOfBenefit","https://basueUrl.com/ExplanationOfBenefit"];
let result = arr.filter(url => !skip.includes(url));

console.log(result);

Answer 3

Answer №2

Filtering an array to remove elements equal to "https://basueUrl.com/Claim" and "https://basueUrl.com/ExplanationOfBenefit"

Answer 4

Filtering an array to remove elements equal to "https://basueUrl.com/Claim" and "https://basueUrl.com/ExplanationOfBenefit"

Answer 5

Answer №3

const urls = [  
    "https://basueUrl.com/Patient",
    "https://basueUrl.com/Organization",
    "https://basueUrl.com/Claim",
    "https://basueUrl.com/Practitioner",
    "https://basueUrl.com/Encounter",
    "https://basueUrl.com/Condition",
    "https://basueUrl.com/Claim",
    "https://basueUrl.com/ExplanationOfBenefit",
    "https://basueUrl.com/Claim",
    "https://basueUrl.com/ExplanationOfBenefit", 
    "https://basueUrl.com/ExplanationOfBenefit"
    ];
        
const filteredUrls = urls.filter(item => item !== "https://basueUrl.com/Claim" && item !== "https://basueUrl.com/ExplanationOfBenefit")

console.log(filteredUrls)

Answer 6

const urls = [  
    "https://basueUrl.com/Patient",
    "https://basueUrl.com/Organization",
    "https://basueUrl.com/Claim",
    "https://basueUrl.com/Practitioner",
    "https://basueUrl.com/Encounter",
    "https://basueUrl.com/Condition",
    "https://basueUrl.com/Claim",
    "https://basueUrl.com/ExplanationOfBenefit",
    "https://basueUrl.com/Claim",
    "https://basueUrl.com/ExplanationOfBenefit", 
    "https://basueUrl.com/ExplanationOfBenefit"
    ];
        
const filteredUrls = urls.filter(item => item !== "https://basueUrl.com/Claim" && item !== "https://basueUrl.com/ExplanationOfBenefit")

console.log(filteredUrls)

Answer 7

Answer №4

Feel free to test out the following code snippet. I trust it will be beneficial to you.

// Replace the original array with this modified array. It generates a new array based on the original one.
const newFilteredArray = Array.filter(url => url !== 'https://basueUrl.com/Claim' && 
   url !== 'https://basueUrl.com/ExplanationOfBenefit');

Answer 8

Feel free to test out the following code snippet. I trust it will be beneficial to you.

// Replace the original array with this modified array. It generates a new array based on the original one.
const newFilteredArray = Array.filter(url => url !== 'https://basueUrl.com/Claim' && 
   url !== 'https://basueUrl.com/ExplanationOfBenefit');

Answer 9

Answer №5

Here is a method you can use to accomplish the scenario described above.

arr.filter(element=>element!=="https://basueUrl.com/Claim"
&& element!=="https://basueUrl.com/ExplanationOfBenefit");

Answer 10

Here is a method you can use to accomplish the scenario described above.

arr.filter(element=>element!=="https://basueUrl.com/Claim"
&& element!=="https://basueUrl.com/ExplanationOfBenefit");

Eliminate values from an array by utilizing either a for loop or a custom filtering function

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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