eliminate the firebase firestore query using onSnapshot

Seeking assistance with the following code snippet:

firebase.firestore()
  .collection("chatrooms")
  .doc(`${chatId}`)
  .collection(`${chatId}`)
  .orderBy("timestamp")
  .limit(50).onSnapshot((snapshot)  => {
    //performing operations on snapshot.val()
  })

I have implemented this listener in my firestore setup and it consistently fetches only the latest 50 documents. My query is: If I want to remove this listener, can I use the following approach?:

firebase.firestore().collection("chatrooms").doc(`${chatId}`).collection(`${chatId}`).off();

I am uncertain if solely invoking .off() on the reference will suffice in this scenario. Usually it works, but due to my ordered and limited query, I wanted to confirm.

Answer №1

Unfortunately, the off() method cannot be found on a CollectionReference. However, you can utilize the onSnapshot method which returns a function that allows you to remove the listener regardless of the query used.

const unsubscribe = firebase.firestore()
  .collection("chatrooms")
  .doc(`${chatId}`)
  .collection(`${chatId}`)
  .orderBy("timestamp")
  .limit(50).onSnapshot((snapshot)  => {
    //perform operations with snapshot.val()
  })

//execute this code to stop the listener
unsubscribe()

If there is a need to unsubscribe from the listener in a different component, you can pass this function as a prop.

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