I've got an array filled with objects
const myArr = [
{k1: 1, k2: 1, k3: 3, k4: 4},
{k1: 1, k2: 2, k3: 3, k4: 4},
{k1: 1, k2: 2, k3: 3, k4: 4},
{k1: 1, k2: 2, k3: 3, k4: 4}
]
I'm attempting to filter these objects, although I don't necessarily have to use the "filter" method.
const filteredObj = myArr.filter(item => item.k2 === 1)However, I only want to retain one specific key-value pair. For example,
console.log(myArr) => {k2: 1}
Implement the use of map() along with object destructuring and property shorthand syntax in the following code snippet:
const array = [
{key1: 1, key2: 1, key3: 3, key4: 4},
{key1: 1, key2: 2, key3: 3, key4: 4},
{key1: 1, key2: 2, key3: 3, key4: 4},
{key1: 1, key2: 2, key3: 3, key4: 4}
]
const filteredObject = array.filter(item => item.key2 === 1).map(({key2}) => ({key2}));
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