Dynamic Routing in AngularJS based on Checkbox Selection

Question

Dynamic Routing in AngularJS based on Checkbox Selection

Currently, I am in the process of mastering Angular JS by working on an HTML Sample project. My goal is to create a user-friendly form where users can input basic information and select checkboxes to load different form pages using UI Routing. The page should dynamically generate navigation links based on the checkboxes selected. Once the form is filled out, it should be saved in a server directory and downloaded to the user's computer.

Although I was able to display all the data as a JSON array in the form, I'm encountering issues after trying to incorporate checklist links for navigation and saving features.

In my App.js file:

I've set up our Angular app and included ngAnimate and ui-router as dependencies

angular.module('formApp', ['ngAnimate', 'ui.router'])

.config(function ($stateProvider, $urlRouterProvider) {
$stateProvider

    .state('form', {
        url: '/form',
        templateUrl: 'form.html',
        controller: 'formController'
    })

    .state('form.profile', {
        url: '/profile',
        templateUrl: 'form-profile.html'
    })

    .state('form.interests', {
        url: '/interests',
        templateUrl: 'form-interests.html'
    })

    .state('form.payment', {
        url: '/payment',
        templateUrl: 'form-payment.html'
    });

$urlRouterProvider.otherwise('/form/profile'); })


.controller('formController', function ($scope) {

$scope.prefContactArray = [];
// code continues...

});

In Form.html:

In Submit Button Page:

In Index:

javascript angularjs angularjs-directive angularjs-scope angular-ui-router

Answer 1

Answer №1

Within your create() function, you are utilizing

$state.go($scope.selected.fruitsList.url)

, which will navigate to a new state. However, it is important to note that the value being passed is a template path rather than a state path.

To ensure correct functionality, consider using

$state.go($scope.selected.fruitsList.state)

. The 'to' parameter of $state.go() should represent the name of the state to transition to or a relative state path. If the path begins with ^ or ., it is considered relative; otherwise, it is absolute.

Answer 2

Within your create() function, you are utilizing

$state.go($scope.selected.fruitsList.url)

, which will navigate to a new state. However, it is important to note that the value being passed is a template path rather than a state path.

To ensure correct functionality, consider using

$state.go($scope.selected.fruitsList.state)

. The 'to' parameter of $state.go() should represent the name of the state to transition to or a relative state path. If the path begins with ^ or ., it is considered relative; otherwise, it is absolute.

Answer 3

Answer №2

$state

In order to navigate through your application, it is essential to utilize the $state service provided by UI Router. By adding this dependency to your controller like shown below:

.controller('formController', function ($scope, $state) {

You will have the ability to easily transition from one state to another within your application using commands such as $state.go('form.payment').

When handling form submissions, make sure to determine the appropriate state to navigate to and conclude with $state.go(stateToGoTo) in your code.

Pro Tip:

For optimal organization and clarity in your routing structure, consider creating a separate route for each individual page instead of utilizing nested children routes. This approach allows you to assign dedicated controllers to each route, streamlining the code separation process and enhancing code readability.

Have you found this information helpful?

Answer 4

$state

In order to navigate through your application, it is essential to utilize the $state service provided by UI Router. By adding this dependency to your controller like shown below:

.controller('formController', function ($scope, $state) {

You will have the ability to easily transition from one state to another within your application using commands such as $state.go('form.payment').

When handling form submissions, make sure to determine the appropriate state to navigate to and conclude with $state.go(stateToGoTo) in your code.

Pro Tip:

For optimal organization and clarity in your routing structure, consider creating a separate route for each individual page instead of utilizing nested children routes. This approach allows you to assign dedicated controllers to each route, streamlining the code separation process and enhancing code readability.

Have you found this information helpful?

Dynamic Routing in AngularJS based on Checkbox Selection

Answer №1

Answer №2

$state

Pro Tip:

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