Divide a string into an array starting from the end

Question

Divide a string into an array starting from the end

I have a unique phrase.

var phrase = "LoremipsumdolorsitametconsectetuadipiscingelitSeddoeiusmodtemporincididuntutlaboreetaliqua";

I am interested in dividing it into chunks of 11 characters starting from the end.

Currently, I use:

function splitPhrase(sentence) {
  return sentence.split( /(?=(?:...........)*$)/ ).map(function(segment){return parseInt(segment)});
}

This operation results in:

[L, oremipsumd, olorsitame, tconsectet, uadipiscin, gelitSeddo, eiusmodtem, porincidun, tutlaboret, aliqua]

Queries:

How can I modify the above function to make it adaptable for breaking strings into segments of any number of characters? (I prefer not manually adding or removing dots)
Is there a way to exclude the first character when splitting the string? (I aim to maintain 'L' as the initial element so the following elements can vary in length from 1 to n)

javascript arrays string numbers

Answer 1

Answer №1

To specify the number of digits you want for each item, wrap them inside curly braces in the regex. Remember that variables cannot be passed directly to a regex using "/" as delimiters; instead, use the RegExp constructor.

var string = "31415926535897932384626433832795028841971693993751058209749445923078164";
function split(a,n) {
  return a.split( new RegExp("(?=(?:.{" + n + "})*$)" )).map(function(x){return parseInt(x)});
}
alert(split(string, 10))

OR

You can also use the match function instead of split.

string.match(/(?!^.).{11}/gm)

DEMO

var string = "31415926535897932384626433832795028841971693993751058209749445923078164";
function split(a,n) {
  return a.match(new RegExp("(?!^.).{" + n + "}|^.", "gm")).map(function(x){return parseInt(x)});
}
alert(split(string, 11))

If you wish to include the remaining characters, including the initial and unmatched ones at the end, you can utilize this regex pattern.

/(?!^.).{11}|^.|.+/gm

DEMO

Answer 2

To specify the number of digits you want for each item, wrap them inside curly braces in the regex. Remember that variables cannot be passed directly to a regex using "/" as delimiters; instead, use the RegExp constructor.

var string = "31415926535897932384626433832795028841971693993751058209749445923078164";
function split(a,n) {
  return a.split( new RegExp("(?=(?:.{" + n + "})*$)" )).map(function(x){return parseInt(x)});
}
alert(split(string, 10))

OR

You can also use the match function instead of split.

string.match(/(?!^.).{11}/gm)

DEMO

var string = "31415926535897932384626433832795028841971693993751058209749445923078164";
function split(a,n) {
  return a.match(new RegExp("(?!^.).{" + n + "}|^.", "gm")).map(function(x){return parseInt(x)});
}
alert(split(string, 11))

If you wish to include the remaining characters, including the initial and unmatched ones at the end, you can utilize this regex pattern.

/(?!^.).{11}|^.|.+/gm

DEMO

Answer 3

Answer №2

Please review the following code snippet:

var _mySplit = function(str, splitLength) {
    var _regEx = '';
    var startSubStringLength = str.length % splitLength
    if(startSubStringLength > 0) {
        _regEx = new RegExp("(^.{1," + startSubStringLength + "})|(.{1," + splitLength +  "})|(.{1,})", "g")
    }
    return str.match(_regEx)
}

Answer 4

Please review the following code snippet:

var _mySplit = function(str, splitLength) {
    var _regEx = '';
    var startSubStringLength = str.length % splitLength
    if(startSubStringLength > 0) {
        _regEx = new RegExp("(^.{1," + startSubStringLength + "})|(.{1," + splitLength +  "})|(.{1,})", "g")
    }
    return str.match(_regEx)
}

Answer 5

Answer №3

Here's a simple solution that does not involve using regular expressions: var string="31415926535897932384626433832795028841971693993751058209749445923078164"; var arr = new Array(); while (!string.length < 10) { substr = string.substr(strlen(string)-10); string = string.replace(substr, ''); arr.push(substr); } var result_arr = arr.reverse();

Answer 6

Here's a simple solution that does not involve using regular expressions: var string="31415926535897932384626433832795028841971693993751058209749445923078164"; var arr = new Array(); while (!string.length < 10) { substr = string.substr(strlen(string)-10); string = string.replace(substr, ''); arr.push(substr); } var result_arr = arr.reverse();

Divide a string into an array starting from the end

Answer №1

Answer №2

Answer №3

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