Disregard any blank spaces when extracting text enclosed in parentheses

I have successfully extracted the text inside the parentheses. While I am able to remove leading whitespace, I am facing difficulty in removing trailing whitespace.

Consider the text 

node     (    t-vr0wkjqky55s9mlh2rtt0u301(asdad)   ) { }

Using my regex \(\s*(.*)\), I get 

t-vr0wkjqky55s9mlh2rtt0u301(asdad)   /
(noting the trailing whitespace; ignore /).

You can view the code in action here.

Below is a live example demonstrating the issue:

var str = "node     (    t-vr0wkjqky55s9mlh2rtt0u301(asdad)   ) { }";
var rex = /\(\s*(.*)\)/;
console.log("[" + rex.exec(str)[1] + "]");

javascriptregex

Answer №1

Feel free to utilize

/\(\s*(.*\S)\s*\)/

Check out the regular expression demonstration.

Additional Information

  • \( represents an opening parenthesis (
  • \s* denotes zero or more whitespace characters
  • (.*\S) - Group 1: matches any sequence of characters followed by a non-whitespace character (consider using [^)\s] instead of \S)
  • \s* signifies zero or more whitespace characters
  • \) stands for a closing parenthesis ).

Revised code snippet:

var str = "node     (    t-vr0wkjqky55s9mlh2rtt0u301(asdad)   ) { }";
var rex = /\(\s*(.*\S)\s*\)/;
console.log("[" + rex.exec(str)[1] + "]");

Answer №2

Here's a handy way to utilize the pattern \(\s*(\S*)\s*\)

const input = "node     (    t-vr0wkjqky55s9mlh2rtt0u301(asdad)   ) { }";
const regex = /\(\s*(\S*)\s*\)/;
console.log("Extracted text: [" + regex.exec(input)[1] + "]");

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