Discovering the power of 11 or determining a variable raised to a specified power in JavaScript

I am currently working on finding the power of a number, specifically 11 to the power of n. While JavaScript has the built-in function Math.pow, I have created my own function that works perfectly. However, it has a time complexity of O(n). Is there a way to reduce this time complexity using a different method?

I have considered using a bit map but have not been successful in implementing it.

function power(x,n) {
    let sum = 1
    for(let i = 0; i < n; i++){
        sum *= x
    }
    
    return sum
}

console.log(power(11,3))

Answer №1

Consider implementing the suggested square method.

The time complexity is O(log2(n)), as shown in this table detailing the function counts:

   n     counts
-------  ------
   100      7
  1000     10
 10000     14
100000     17

function power(x, n) {
    if (n === 1) return x;
    let temp = power(x, n >> 1);
    return n % 2
        ? x * temp * temp
        : temp * temp;
}

console.log(power(11, 3)); // Result: 1331 with 2 recursive calls

Answer №2

Here is a potential strategy:

function calculatePower(x, n) {
  let result = 1;
  let accumulator = x;
  while (n > 0) {
    if (n & 1) result *= accumulator;
    accumulator *= accumulator;
    n >>= 1;
  }
  return result;
}

console.log(calculatePower(11, 0)); // 1
console.log(calculatePower(11, 1)); // 11
console.log(calculatePower(11, 2)); // 121
console.log(calculatePower(11, 3)); // 1331
console.log(calculatePower(11, 5)); // 161051
console.log(calculatePower(11, 8)); // 214358881 etc.

The concept involves storing the results of each squared iteration of the original number (x). With each step, n is halved, resulting in an O(log n) complexity instead of O(n). This approach bears resemblance to @NinaScholz's solution but is iterative rather than recursive, which may be deemed advantageous.

(It is advisable to include safeguards for MAX_SAFE_INTEGER in any real-world application, though we are primarily focusing on the algorithm here)

Answer №3

Check out this simple JavaScript code for implementing the square method:

function calculateSquare(x,n){
   if(n < 0) 
     return calculateSquare(1 / x, -n);
   else if(n === 0) 
     return  1;
   else if(n === 1) 
     return  x ;
   else if(n %2===0) 
     return calculateSquare(x * x,  n / 2);
   else 
     return x * calculateSquare(x * x, (n - 1) / 2);
}

I have also put together a performance test comparing different techniques mentioned by other users. Feel free to take a look:

Performance Test

Answer №4

Although not as elegant as some other solutions, this implementation is faster than the original.

const calculatePower = (base, exponent) => {
   return Array.apply(null, Array(exponent)).reduce((result, value) => result * base, 1);
}

Answer №5

Unfortunately, I am unable to directly leave a comment on your inquiry at the moment. However, I will try my best to provide a helpful response to your question. Does this align with what you were seeking?

const myPow = (x, y) => x ** y;

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