Discovering the highest number of consecutive elements in a JavaScript array

Question

Discovering the highest number of consecutive elements in a JavaScript array

Having trouble wrapping my head around a particular issue and could use some insight from those with more experience. I am dealing with an array containing anywhere from 10 to 500 values, all either true or false but in random order. My goal is to determine the maximum consecutive occurrence of false within this array. For example:

[false, false, true, false, true, false, true, false, false, false]

Answer should be 3, as false appears three times consecutively at most. While it seems like a common problem, I have not been able to find a solution through my searches. Any assistance would be greatly appreciated!

javascript arrays

Answer 1

Answer №1

To track consecutive false values, you can use a single value and update it based on the current sequence length. Whenever the value is set to true, reset the counter to zero.

var arr = [false, false, true, false, true, false, true, false, false, false]
var count = 0, maxCount = 0;

arr.forEach(function(element) {
  element == false ? count++ : count = 0;
  if (count > maxCount) maxCount = count;
})

console.log(maxCount)

Answer 2

To track consecutive false values, you can use a single value and update it based on the current sequence length. Whenever the value is set to true, reset the counter to zero.

var arr = [false, false, true, false, true, false, true, false, false, false]
var count = 0, maxCount = 0;

arr.forEach(function(element) {
  element == false ? count++ : count = 0;
  if (count > maxCount) maxCount = count;
})

console.log(maxCount)

Answer 3

Answer №2

To achieve this, you can utilize the forEach method along with an internal counter like so:

console.log( calculateConsecutive([true, true, false, true, false, true, true, false, false, true]) );

function calculateConsecutive( arr )
{
   var count = 0;
  
   arr.forEach(function(item) {  
     (item == true) ? count++ : count = 0;
  });
  
  return count;
}

Answer 4

To achieve this, you can utilize the forEach method along with an internal counter like so:

console.log( calculateConsecutive([true, true, false, true, false, true, true, false, false, true]) );

function calculateConsecutive( arr )
{
   var count = 0;
  
   arr.forEach(function(item) {  
     (item == true) ? count++ : count = 0;
  });
  
  return count;
}

Answer 5

Answer №3

Check out this custom function for finding the longest sequence of consecutive false values in an array:

function findLongestFalseSequence(arr){
    var maxLength = 0;
    var foundFalse = false;
    var currentLength = 0;
    for (var j = 0; j < arr.length; j++) {
        foundFalse = foundFalse || arr[j];
        if(foundFalse === true){
            foundFalse = false;
            currentLength = 0;
        }
        else{
            currentLength++;
            if(currentLength > maxLength){
                maxLength = currentLength;
            }
        }
    }
    return maxLength;
}

var sampleArray = [false, false, true, false, true, false, true, false, false, false];

findLongestFalseSequence(sampleArray);
3

Answer 6

Check out this custom function for finding the longest sequence of consecutive false values in an array:

function findLongestFalseSequence(arr){
    var maxLength = 0;
    var foundFalse = false;
    var currentLength = 0;
    for (var j = 0; j < arr.length; j++) {
        foundFalse = foundFalse || arr[j];
        if(foundFalse === true){
            foundFalse = false;
            currentLength = 0;
        }
        else{
            currentLength++;
            if(currentLength > maxLength){
                maxLength = currentLength;
            }
        }
    }
    return maxLength;
}

var sampleArray = [false, false, true, false, true, false, true, false, false, false];

findLongestFalseSequence(sampleArray);
3

Answer 7

Answer №4

let myArray = [true, true, false, false, true, true, true];
let lengthOfArray = myArray.length;
let greatestCount = 0;
let currentCounter = 0;
let previousElement;

for(let j = 0; j < lengthOfArray; j++) {
    if(previousElement === myArray[j]) {
        currentCounter++;
    } else {
        if(currentCounter > greatestCount) {
            greatestCount = currentCounter;
        }
        currentCounter = 1;
    }
    previousElement = myArray[j];
}
console.log(greatestCount);

This code snippet should meet your requirements

Answer 8

let myArray = [true, true, false, false, true, true, true];
let lengthOfArray = myArray.length;
let greatestCount = 0;
let currentCounter = 0;
let previousElement;

for(let j = 0; j < lengthOfArray; j++) {
    if(previousElement === myArray[j]) {
        currentCounter++;
    } else {
        if(currentCounter > greatestCount) {
            greatestCount = currentCounter;
        }
        currentCounter = 1;
    }
    previousElement = myArray[j];
}
console.log(greatestCount);

This code snippet should meet your requirements

Answer 9

Answer №5

Check out this clever one-liner solution:

var arr = [false, false, false, true, false, false, true, false, false, true];

var consec = arr.join('').split('true').reduce((i, x) => Math.max((x.match(/false/g) || []).length, i), 0);

To break it down:

Convert the array into a string
Split the new string based on the values we don't want in order to create an array of consecutive items as strings
In the reduce function, count the number of matches using a regex match and find the maximum number of those matches.

Note that this method works best with binary lists like [true, false], [1,0], etc.

Check out the Fiddle here.

Answer 10

Check out this clever one-liner solution:

var arr = [false, false, false, true, false, false, true, false, false, true];

var consec = arr.join('').split('true').reduce((i, x) => Math.max((x.match(/false/g) || []).length, i), 0);

To break it down:

Convert the array into a string
Split the new string based on the values we don't want in order to create an array of consecutive items as strings
In the reduce function, count the number of matches using a regex match and find the maximum number of those matches.

Note that this method works best with binary lists like [true, false], [1,0], etc.

Check out the Fiddle here.

Discovering the highest number of consecutive elements in a JavaScript array

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Similar questions

Mastering the use of expressions in ng-click and ng-show in AngularJS

Determine whether a WebElement contains a particular content within the :after pseudo class

What could be causing my JavaScript code to fail to add data when the submit button is

javascript issue with attribute manipulation

Layout of CSS grid being created dynamically

UV mapping with Plane BufferGeometry in Three.js

Utilizing the sum of neighboring values to subsample a 3D array

Data-binding in Angular ceases to function properly in the presence of duplicate values within an

The Angular interfaces fail to load on every web browser

Sequelize - Leveraging Associations in Where Clauses

How can one determine the existence of a collection or sub-collection?

Having trouble importing the module I developed in Node

Why is my array.sort statement in ReactJS not functioning properly?

Tips for accessing a variable located in a different directory

Tips for customizing the border radius style of the menu in Vuetify's v-autocomplete component

A guide on defining global variables in React JS

Tips for transferring a file to PocketBase using NodeJs

Print out the error message: "ERROR [ExceptionsHandler] Unable to access the property 'log' as it is undefined."

Unable to Define Headers in Fetch GET Call

The challenge is to determine the highest count of unique smaller elements present on the right side of each element in an array