Looking at the structure below:
item: {
b: null,
c: "asd",
i: 10,
q: 10,
s: Array [237,241]}
In addition, there is an array of ids available:
var ids = [237, 238, 239, 240, 242, 243...]
I am unsure about how to validate whether the ids mentioned above are present in the 's' property and then store those items in a new array or object.
for (var key in items) {
for (var i in items[key].s) {
//...
}
}
if(elements.t.some(element => codes.includes(element))) alert("yahoo");
To determine if any of the elements' codes are present in the codes array, you can also use a for loop:
for(var j = 0; j < elements.t.length; j++){
if( codes.includes( elements.t[j] )){
alert("yahoo");
}
}
To achieve this, you can use a combination of Array.filter and Array.indexOf. If you are not utilizing any code transpiler, it is advisable to opt for indexOf over includes due to better browser support.
var matchingIds = items.filter(x => ids.indexOf(x) !== -1);
// The variable 'matchingIds' now holds the IDs that were found in both 'ids' and 'items'
var items = {
b: null,
c: "asd",
i: 10,
q: 10,
s: [237,241]
}
var ids = [237, 238, 239, 240, 242, 243];
var matchingIds = items.s.filter(x => ids.indexOf(x) !== -1);
console.log(matchingIds);let product = {
name: "apple",
price: 1.50,
quantity: 10
}
let prices = [1.50, 2.00, 3.00, 4.50];
// method 1
for(let i = 0; i < prices.length; i++){
if( ~prices.indexOf(product.price)){
console.log(product.price);
}
}
//method 2
let filteredPrices = prices.filter(x => ~product.price.indexOf(x));
console.log(filteredPrices);filteredIds = ids.filter(id => items.s.includes(id))
Select only the ids from the list that are included in items.s.
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