Discovering the corresponding elements within an array of objects

Within my array of objects, I am performing a search

let arr = [
    { name:"string 1", arrayWithvalue:"1,2", other: "that" },
    { name:"string 2", arrayWithvalue:"2", other: "that" },
    { name:"string 2", arrayWithvalue:"2,3", other: "that" },
    { name:"string 2", arrayWithvalue:"4,5", other: "that" },
    { name:"string 2", arrayWithvalue:"4", other: "that" },
];
var item  = arr.find(item => item.arrayWithvalue === '4'); 
console.log(item)

The desired outcome is to obtain an array containing these two rows

{ name:"string 2", arrayWithvalue:"4,5", other: "that" },
{ name:"string 2", arrayWithvalue:"4", other: "that" }

However, only one row is being returned which is the first match.

{ name:"string 2", arrayWithvalue:"4", other: "that" }

I prefer not to rely on external libraries for a solution. Is there a way to capture all the matches that satisfy the set criteria?

Answer №1

There are two important points to consider here. Firstly, when using Array.find(), it will return the first matching element and if no match is found, it will return undefined. On the other hand, Array.filter will return a new array containing all matching elements, or an empty array [] if there are no matches.

The second point to keep in mind is that if you want to find values like 4,5, you need to search within the string rather than making a strict comparison. This can be done by using indexOf, which will return the position of the matching string or -1 if there is no match.


For example:

const arr = [
  {
    name: 'string 1',
    arrayWithvalue: '1,2',
    other: 'that',
  },
  {
    name: 'string 2',
    arrayWithvalue: '2',
    other: 'that',
  },
  {
    name: 'string 2',
    arrayWithvalue: '2,3',
    other: 'that',
  },
  {
    name: 'string 2',
    arrayWithvalue: '4,5',
    other: 'that',
  },
  {
    name: 'string 2',
    arrayWithvalue: '4',
    other: 'that',
  },
];

const items = arr.filter(item => item.arrayWithvalue.indexOf('4') !== -1);

console.log(items);

Answer №2

Utilize the array filter approach.

arr.filter(result => result.arrayWithvalue.indexOf('4') !== -1);

Answer №3

To get the desired result, replace the find method with the filter method. The new array generated will only include items that pass the condition set by the callback function.

Answer №4

Array.prototype.find() follows the guidelines outlined in the MDN specification: it will retrieve the value of the first element in the array that meets the criteria set by the testing function.

For a different approach, consider using the filter function .filter(), which returns an array containing all elements that pass your testing function.

Answer №5

Using the filter method in combination with the charAt function.

const filteredResult = arrayToFilter.filter(item => item.arrayWithvalue.charAt(0) === '4');

Answer №6

Implementing array.filter method:

var array = [
    { item:"apple", values:"1,2", category: "fruit" },
    { item:"banana", values:"2", category: "fruit" },
{ item:"orange", values:"2,3", category: "fruit" },
{ item:"grape", values:"4,5", category: "fruit" },
{ item:"pear", values:"4", category: "fruit" },
];

var result = array.filter(element => element.values.split(',')[0] === '4');
console.log(result);

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