discovering the absence of any letters within an array

Question

discovering the absence of any letters within an array

Looking for a way to find multiple missing letters in an array? Check out this code snippet:

function missingLetters(str) {
  var nums = str.split('').map(function(letter){
    return letter.charCodeAt();
  })
  
  var result = [];
  
  for(var i=0; i<nums.length - 1; i++){
    if(nums[i+1] - nums[i] >1){
      for(var j = nums[i]+1 ; j< nums[i+1]; j++){
        result.push(String.fromCharCode(j));
      }
    }
  }
  
  return result;
}

missingLetters("abceghj");

This revised code will loop through every element in the array and return an array of all missing letters between existing ones.

javascript arrays loops

Answer 1

Answer №1

Instead of immediately returning, it is recommended to store the values in an array or string and return them at the end

function findMissingLetter(str) {
  var characters = str.split('').map(function(letter){
    return letter.charCodeAt();
  })
  const missingLetters = [];
  for(var i=0; i<characters.length; i++){
    if(characters[i+1] - characters[i] >1){
      missingLetters.push(String.fromCharCode(characters[i]+1))
    }
  }
  return missingLetters
}

console.log(findMissingLetter("abcegi"));

Answer 2

Instead of immediately returning, it is recommended to store the values in an array or string and return them at the end

function findMissingLetter(str) {
  var characters = str.split('').map(function(letter){
    return letter.charCodeAt();
  })
  const missingLetters = [];
  for(var i=0; i<characters.length; i++){
    if(characters[i+1] - characters[i] >1){
      missingLetters.push(String.fromCharCode(characters[i]+1))
    }
  }
  return missingLetters
}

console.log(findMissingLetter("abcegi"));

Answer 3

Answer №2

Instead of returning each letter individually from the function, it is recommended to return an array or string as a whole

function findMissingLetters(str) {
  var missingLetters = [], charCodes = str.split('').map(function(letter){
    return letter.charCodeAt();
  })
  
  for(var i=0; i<charCodes.length; i++){
    if(charCodes[i+1] - charCodes[i] >1){
      missingLetters.push(String.fromCharCode(charCodes[i]+1))
    }
  }
  return missingLetters
}

console.log(findMissingLetters("abce"));
console.log(findMissingLetters("abceghj"));

If you need a more robust solution that can handle duplicates and letters in the wrong order, check out Marcus' implementation here: https://codepen.io/marcusparsons/pen/YYxrpG

Answer 4

Instead of returning each letter individually from the function, it is recommended to return an array or string as a whole

function findMissingLetters(str) {
  var missingLetters = [], charCodes = str.split('').map(function(letter){
    return letter.charCodeAt();
  })
  
  for(var i=0; i<charCodes.length; i++){
    if(charCodes[i+1] - charCodes[i] >1){
      missingLetters.push(String.fromCharCode(charCodes[i]+1))
    }
  }
  return missingLetters
}

console.log(findMissingLetters("abce"));
console.log(findMissingLetters("abceghj"));

If you need a more robust solution that can handle duplicates and letters in the wrong order, check out Marcus' implementation here: https://codepen.io/marcusparsons/pen/YYxrpG

Answer 5

Answer №3

In order to return a collection of values, you must use either an array or a string as you can't return multiple values at once. One way to achieve this is by modifying your function to store the found values in an array.

function findMissingLetters(str) {
  var result = [];
  var letters = str.split('').map(function(char){
    return char.charCodeAt();
  });

  for (var i = 0; i < letters.length; i++) {
    if(letters[i + 1] - letters[i] > 1) {
      result.push(String.fromCharCode(letters[i]+1));
    }
  }
  return result;
}

Answer 6

In order to return a collection of values, you must use either an array or a string as you can't return multiple values at once. One way to achieve this is by modifying your function to store the found values in an array.

function findMissingLetters(str) {
  var result = [];
  var letters = str.split('').map(function(char){
    return char.charCodeAt();
  });

  for (var i = 0; i < letters.length; i++) {
    if(letters[i + 1] - letters[i] > 1) {
      result.push(String.fromCharCode(letters[i]+1));
    }
  }
  return result;
}

discovering the absence of any letters within an array

Answer №1

Answer №2

Answer №3

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