Discovering all links in Selenium by implementing Javascript

I currently have this Selenium Java code snippet. Does anyone know how I can convert it to JavaScript?

const webdriver = require('selenium-webdriver');
const By = webdriver.By;
const firefox = require('selenium-webdriver/firefox');

(async function findAllLinks() {
    let driver = await new webdriver.Builder().forBrowser('firefox').setFirefoxOptions(new firefox.Options()).build();
    await driver.get("http://toolsqa.com/");
    let links = await driver.findElements(By.tagName("a"));
    console.log(links.length);

    for (let i = 0; i < links.length; i++) {
        console.log(await links[i].getText());
    }
})();

Answer №1

Here's a different approach:

let allLinks, count, index, currentLink, textContent;

allLinks = document.links;
count = allLinks.length;
console.log(count);
for (index = 0; index < count; index += 1) {
  currentLink = allLinks[index]; 
  textContent = (currentLink.textContent || currentLink.innerText).trim();
  console.log(textContent);
}

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