My JavaScript object is deeply nested with an infinite number of children, each containing a value.
var object = {
value: 1,
children: {
value: 10,
children:{
value: 2,
children: {...}
}
}
}
I've tried creating a recursive function to traverse the entire object structure, but so far it only goes down to a certain depth.
When your linked list is transformed into an array, you have the option to utilize Array.prototype.reduce() with an accumulator that consists of a tuple containing min and max. The process begins with initial values of Infinity for min and -Infinity for max in order to align with the functions found in Math.min() and Math.max():
const object = {
value: 1,
children: {
value: 10,
children: {
value: 2,
children: {
value: 5,
children: null
}
}
}
}
const flat = o => o == null || o.value == null ? [] : [o.value, ...flat(o.children)]
const [min, max] = flat(object).reduce(
([min, max], value) => [Math.min(min, value), Math.max(max, value)],
[Infinity, -Infinity]
)
console.log(min, max)Given that the children object only contains a single value (compared to an array with multiple values), the recursive function presented here is straightforward. The function follows a simple logic where if there are no children, then both the minimum and maximum values are equal to the sole value. On the other hand, if there are children, the function recursively navigates through them to determine the minimum and maximum values:
var object = {
value: -10,
children: {
value: 4,
children:{
value: 200,
children: {
value: -100,
children: null
}
}
}
}
function getMinMax(obj) {
if (!obj.children || obj.children.value == undefined)
return {min: obj.value, max: obj.value}
else {
let m = getMinMax(obj.children)
return {min: Math.min(obj.value, m.min), max: Math.max(obj.value, m.max)}
}
}
console.log(getMinMax(object))To make a small adjustment, simply switch from using Math.max to Math.min
var test = {
value: 1,
children: {
value: 10,
children:{
value: 2,
children: {}
}
}
}
function findMaxValue(obj) {
if (Object.keys(obj.children).length === 0) {
return obj.value;
}
return Math.min(obj.value, findMaxValue(obj.children))
}
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