Discover the position of characters within a given string

Question

Discover the position of characters within a given string

I'm trying to accomplish a task similar to this:

If the array [ "a", "b", "c" ] includes any of the characters in the constant word = "abracadabra", I want to retrieve that character along with its position in const word.

My attempt so far looks like this:

const word = "abracadabra";
const input = ["a", "b", "c"];
for (let i = 0; i< word.length; i++) {
  if (input.includes(word(i))) {
  console.log(i + (word(i)));
  }
}

However, it's not working as expected. Can someone assist me with the logic and syntax? I am new to coding, thank you for your time and help!

javascript arrays string include

Answer 1

Answer №1

To access a field of an array, remember to use square brackets instead of parentheses which are meant for calling functions.

const term = "terminator";
const chars = ["t", "e", "r"];

for (let j = 0; j < term.length; j++) {
  if (chars.includes(term[j])) {
      console.log(j + term[j]);
  }
}

Answer 2

To access a field of an array, remember to use square brackets instead of parentheses which are meant for calling functions.

const term = "terminator";
const chars = ["t", "e", "r"];

for (let j = 0; j < term.length; j++) {
  if (chars.includes(term[j])) {
      console.log(j + term[j]);
  }
}

Answer 3

Answer №2

Since your query specified:

provide me with the character and its position in const word

you can utilize RegExp.prototype.exec

const word = "abracadabra";
const input = ["a", "b", "c"];

input.forEach(c => {
  const re = new RegExp(c, "g");
  let m;
  while (m = re.exec(word)) console.log(`${c} found at index ${m.index}`);
});

Another efficient method to accomplish the same task is by using Array.prototype.reduce():

const word = "abracadabra";
const input = ["a", "b", "c"];

const res = input.reduce((ob, c) => {
  ob[c] = [...word].reduce((a, w, i) => {
    if (w === c) a.push(i);
    return a;
  }, []);
  return ob;
}, {});


console.log(res);

This approach will generate an Object, with each character as a property containing an array of its positions in the word:

{
  "a": [0, 3, 5, 7, 10],
  "b": [1, 8],
  "c": [4]
}

Answer 4

Since your query specified:

provide me with the character and its position in const word

you can utilize RegExp.prototype.exec

const word = "abracadabra";
const input = ["a", "b", "c"];

input.forEach(c => {
  const re = new RegExp(c, "g");
  let m;
  while (m = re.exec(word)) console.log(`${c} found at index ${m.index}`);
});

Another efficient method to accomplish the same task is by using Array.prototype.reduce():

const word = "abracadabra";
const input = ["a", "b", "c"];

const res = input.reduce((ob, c) => {
  ob[c] = [...word].reduce((a, w, i) => {
    if (w === c) a.push(i);
    return a;
  }, []);
  return ob;
}, {});


console.log(res);

This approach will generate an Object, with each character as a property containing an array of its positions in the word:

{
  "a": [0, 3, 5, 7, 10],
  "b": [1, 8],
  "c": [4]
}

Answer 5

Answer №3

const phrase = "abracadabra";
const letters = ["a", "b", "c"];
for (let index = 0; index < phrase.length; index++) {
  if (letters.includes(phrase[index])) {
    console.log(index + (phrase[index]));
  }
}

Remember to utilize the square bracket phrase[i] instead of phrase(i).

Answer 6

const phrase = "abracadabra";
const letters = ["a", "b", "c"];
for (let index = 0; index < phrase.length; index++) {
  if (letters.includes(phrase[index])) {
    console.log(index + (phrase[index]));
  }
}

Remember to utilize the square bracket phrase[i] instead of phrase(i).

Answer 7

Answer №4

After formulating and posting the question, a better solution came to mind. I've now come up with a working code snippet:

const word = "abracadabra";
const inPut = ["a", "b", "c"];
for (let i = 0; i< word.length; i++) {
    for (let j = 0; j< (inPut.length); j++) {
        if (word.charAt(i).includes(inPut[j])) {
            console.log(i + (word.charAt(i)));

        }
    }
}

Answer 8

After formulating and posting the question, a better solution came to mind. I've now come up with a working code snippet:

const word = "abracadabra";
const inPut = ["a", "b", "c"];
for (let i = 0; i< word.length; i++) {
    for (let j = 0; j< (inPut.length); j++) {
        if (word.charAt(i).includes(inPut[j])) {
            console.log(i + (word.charAt(i)));

        }
    }
}

Answer 9

Answer №5

for(let i=0;i<input.length;i++){
  if(word.indexOf(input[i]) != -1){
    console.log('word includes ',input[i])
  }
}

My solution should help address the issue you're facing.

Answer 10

for(let i=0;i<input.length;i++){
  if(word.indexOf(input[i]) != -1){
    console.log('word includes ',input[i])
  }
}

My solution should help address the issue you're facing.

Discover the position of characters within a given string

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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