Discover the highest number within an array made up of multiple arrays

Question

Discover the highest number within an array made up of multiple arrays

JavaScript Challenge:

function findLargestInEachSubArray(arr) {


var maxValue = 0;
var largestNumbers = [];

for(var i = 0; i < arr.sort().reverse().length; i++){
  for(var j = 0; j < arr[i].length; j++){

    if(maxValue < arr[i][j]){
      maxValue = arr[i][j]; // issue here
      //largestNumbers.push(maxValue);  this will only add the first element in each subset
      // result [4,5,13,27,32,35,37,39,1000,1001]
    }

  }
}

return largestNumbers;

}

findLargestInEachSubArray([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);


//  Expected Outcome:

// [5, 27, 39, 1001]

I'm stuck on this problem. How can I modify my function to correctly find and store the biggest number from each sub-array into the largestNumbers array using nested for-loops?

javascript arrays

Answer 1

Answer №1

Considering your preference for a for loop:

const findLargestOfFour = (arr) => {
  let largestNumbers = [];
  for(let index = 0; index < arr.length; index++) {
    largestNumbers[index] = arr[index].sort((a,b) => b - a)[0];
  }
  return largestNumbers;
}

This function will sort the subarrays and extract the largest number from each one.

Answer 2

Considering your preference for a for loop:

const findLargestOfFour = (arr) => {
  let largestNumbers = [];
  for(let index = 0; index < arr.length; index++) {
    largestNumbers[index] = arr[index].sort((a,b) => b - a)[0];
  }
  return largestNumbers;
}

This function will sort the subarrays and extract the largest number from each one.

Answer 3

Answer №2

Consider using the map() function as an alternative to traditional for loops.

var array = [[8, 11, 3, 7], [15, 29, 20, 28], [38, 43, 45, 47], [2000, 2001, 1857, 12]]

function findMaxInArray(data) {
  return data.map(element => Math.max.apply(null, element))
}
console.log(findMaxInArray(array))

Answer 4

Consider using the map() function as an alternative to traditional for loops.

var array = [[8, 11, 3, 7], [15, 29, 20, 28], [38, 43, 45, 47], [2000, 2001, 1857, 12]]

function findMaxInArray(data) {
  return data.map(element => Math.max.apply(null, element))
}
console.log(findMaxInArray(array))

Answer 5

Answer №3

Utilizing the spread syntax with Math.max can simplify your code.

function maxValueFromArray(data) {
    return data.map(arr => Math.max(...arr))
}

var numbers = [[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]

console.log(maxValueFromArray(numbers));

Answer 6

Utilizing the spread syntax with Math.max can simplify your code.

function maxValueFromArray(data) {
    return data.map(arr => Math.max(...arr))
}

var numbers = [[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]

console.log(maxValueFromArray(numbers));

Answer 7

Answer №4

Perhaps not the most efficient solution, but this code should get the job done

function findLargestInEachArray(arr) {
   return arr.map(function (subArr) {
      return Math.max.apply(null, subArr);
      // return Math.max(...subArr);
   });
}

findLargestInEachArray([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);

Answer 8

Perhaps not the most efficient solution, but this code should get the job done

function findLargestInEachArray(arr) {
   return arr.map(function (subArr) {
      return Math.max.apply(null, subArr);
      // return Math.max(...subArr);
   });
}

findLargestInEachArray([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);

Answer 9

Answer №5

When dealing with arrays and sub array items of significant size, this approach appears to be the most effective.

let arr = [[14, 5, 11, 33], [3, 17, 22, 16], [62, 25, 57, 89], [10001, 1901, 887, 11]],
    result = arr.map(array => array.reduce((previous,current) => previous > current ? previous : current));
console.log(result);

Answer 10

When dealing with arrays and sub array items of significant size, this approach appears to be the most effective.

let arr = [[14, 5, 11, 33], [3, 17, 22, 16], [62, 25, 57, 89], [10001, 1901, 887, 11]],
    result = arr.map(array => array.reduce((previous,current) => previous > current ? previous : current));
console.log(result);

Answer 11

Answer №6

I approached the problem in this manner, ensuring it handles both negative and positive numbers effectively.

function findLargestInArrays(arr) {
  var maxValues = [];
  for(let i = 0; i < arr.length ; i++){
    let maxValue = -10000000;
    for(let j = 0; j < arr[i].length; j++)
      if(arr[i][j] > maxValue)
         maxValue = arr[i][j];
      
    maxValues[i] = maxValue;
  }
console.log(maxValues)

  return maxValues;
}

findLargestInArrays([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
findLargestInArrays([[4, 9, 1, 3], [13, 35, 18, 26], [32, 35, 97, 39], [1000000, 1001, 857, 1]]);
findLargestInArrays([[17, 23, 25, 12], [25, 7, 34, 48], [4, -10, 18, 21], [-72, -3, -17, -10]])

Answer 12

I approached the problem in this manner, ensuring it handles both negative and positive numbers effectively.

function findLargestInArrays(arr) {
  var maxValues = [];
  for(let i = 0; i < arr.length ; i++){
    let maxValue = -10000000;
    for(let j = 0; j < arr[i].length; j++)
      if(arr[i][j] > maxValue)
         maxValue = arr[i][j];
      
    maxValues[i] = maxValue;
  }
console.log(maxValues)

  return maxValues;
}

findLargestInArrays([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
findLargestInArrays([[4, 9, 1, 3], [13, 35, 18, 26], [32, 35, 97, 39], [1000000, 1001, 857, 1]]);
findLargestInArrays([[17, 23, 25, 12], [25, 7, 34, 48], [4, -10, 18, 21], [-72, -3, -17, -10]])

Discover the highest number within an array made up of multiple arrays

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

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