Discover supplementary characters to incorporate into a JavaScript string

Question

Discover supplementary characters to incorporate into a JavaScript string

I am facing a challenge with identifying three added characters in the second string that are not present in the first string. These added characters could be located anywhere within the string.

For example:

string1 = "hello"
string2 = "aaahello"

// => 'a'

The added characters may also overlap with existing characters in the original string, as shown below:

string1 = "abcde"
string2 = "2db2a2ec"

// => '2'

In another scenario:

string1 = "aabbcc"
string2 = "aacccbbcc"

// => 'c'

I have attempted to address this issue using the following function, but it does not accurately pinpoint the three identical added characters in the second string:

function addedChar(a, b){
    var i = 0;
    var j = 0;
    var result = "";

    while (j < b.length)
    {
        if (a[i] != b[j] || i == a.length)
            result += b[j];
        else
            i++;
        j++;
    }

    return result;
}

javascript

Answer 1

Answer №1

How do you feel about this? It may seem like it only works one way, but in reality, it can work both ways.

str1 = "aabbcc";
str2 = "aacccbbcc";
differences = str2;

for(let j = 0; j < str1.length; j++) {
  const character = str1[j];
  differences = differences.replace((new RegExp(`${character}`)), '');
}

//ccc
console.log(differences);

Answer 2

How do you feel about this? It may seem like it only works one way, but in reality, it can work both ways.

str1 = "aabbcc";
str2 = "aacccbbcc";
differences = str2;

for(let j = 0; j < str1.length; j++) {
  const character = str1[j];
  differences = differences.replace((new RegExp(`${character}`)), '');
}

//ccc
console.log(differences);

Answer 3

Answer №2

Effective approach:

Innovative solution using JavaScript:

let str1 = "aabbcc";
let str2 = "aacccbbcc";

function characterCount (str) {
  let count = {};
  for (let i = 0; i < str.length; i++) {
      count[str[i]] = (count[str[i]] || 0) + 1; 
  }
  return count;
}

let countStr1 = characterCount(str1);
let countStr2 = characterCount(str2);

console.log(Object.keys(countStr2).filter(char => countStr2[char] != countStr1[char])[0]);

Answer 4

Effective approach:

Innovative solution using JavaScript:

let str1 = "aabbcc";
let str2 = "aacccbbcc";

function characterCount (str) {
  let count = {};
  for (let i = 0; i < str.length; i++) {
      count[str[i]] = (count[str[i]] || 0) + 1; 
  }
  return count;
}

let countStr1 = characterCount(str1);
let countStr2 = characterCount(str2);

console.log(Object.keys(countStr2).filter(char => countStr2[char] != countStr1[char])[0]);

Answer 5

Answer №3

function identifyAddedChars(str1, str2) {
  return str1.split("").reduce((s2, char) => {
    const idx = s2.indexOf(char)
    return s2.slice(0, idx).concat(s2.slice(idx + 1))
  }, str2.split("")).join("")[0]
}

let str1
let str2

str1 = "hello"
str2 = "aaahello"
console.log(identifyAddedChars(str1, str2)) // => 'a'

str1 = "abcde"
str2 = "2db2a2ec"
console.log(identifyAddedChars(str1, str2))  // => '2'

str1 = "aabbcc"
str2 = "aacccbbcc"
console.log(identifyAddedChars(str1, str2)) // => 'c'

Answer 6

function identifyAddedChars(str1, str2) {
  return str1.split("").reduce((s2, char) => {
    const idx = s2.indexOf(char)
    return s2.slice(0, idx).concat(s2.slice(idx + 1))
  }, str2.split("")).join("")[0]
}

let str1
let str2

str1 = "hello"
str2 = "aaahello"
console.log(identifyAddedChars(str1, str2)) // => 'a'

str1 = "abcde"
str2 = "2db2a2ec"
console.log(identifyAddedChars(str1, str2))  // => '2'

str1 = "aabbcc"
str2 = "aacccbbcc"
console.log(identifyAddedChars(str1, str2)) // => 'c'

Discover supplementary characters to incorporate into a JavaScript string

Answer №1

Answer №2

Answer №3

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