Discover how to transform a collection of numbers into a more expansive set that accurately reflects the original set

Question

Discover how to transform a collection of numbers into a more expansive set that accurately reflects the original set

Consider an array with the following elements: [1,2,5,18,17,8]. Now, if you want to transform this array into a new one with a length of 40 while maintaining the same progression, you can use the following code:

a = [1,2,5,18,17,8];

stepSize = 1 / (40 / a.length);

You can achieve this by doing something like the following:

steps = [];

for( var i = 0; i < 1; i+= stepSize) {
  steps.push(d3.interpolate(a[0],a[1])(i));
}

You would then repeat this process for all the elements in the original array. Is there perhaps a more efficient way to accomplish this task?

javascript d3.js

Answer 1

Answer №1

It seems like you want to visualize these data points with a smooth curve. To achieve this, you can utilize the line.interpolate() function available at this link.

If you already have a solution that works for you, here's a helpful tip: Instead of iterating over stepSize repeatedly, calculate it once and then multiply it by the index (i) in each loop iteration from 0 to 40. This method can help you avoid precision issues.

Your algorithm has been optimized, tested, and is now functional:

var a = [1,5,12,76,1,2];
var steps = 24;
var ss = (a.length-1) / (steps-1);

var result = new Array(steps);
for (var i=0; i<steps; i++) {
    var progress = ss * i;
    var left = Math.floor(progress);
    var right = Math.ceil(progress);
    var factor = progress - left;
    result[i] = (1 - factor) * a[left] + (factor) * a[right];
    // You can also use d3.interpolateNumber(a[left], a[right], factor) which provides the same result.
}

console.log(result);

Answer 2

It seems like you want to visualize these data points with a smooth curve. To achieve this, you can utilize the line.interpolate() function available at this link.

If you already have a solution that works for you, here's a helpful tip: Instead of iterating over stepSize repeatedly, calculate it once and then multiply it by the index (i) in each loop iteration from 0 to 40. This method can help you avoid precision issues.

Your algorithm has been optimized, tested, and is now functional:

var a = [1,5,12,76,1,2];
var steps = 24;
var ss = (a.length-1) / (steps-1);

var result = new Array(steps);
for (var i=0; i<steps; i++) {
    var progress = ss * i;
    var left = Math.floor(progress);
    var right = Math.ceil(progress);
    var factor = progress - left;
    result[i] = (1 - factor) * a[left] + (factor) * a[right];
    // You can also use d3.interpolateNumber(a[left], a[right], factor) which provides the same result.
}

console.log(result);

Discover how to transform a collection of numbers into a more expansive set that accurately reflects the original set

Answer №1

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