Develop a custom function to determine if every element within the array is identical

Issue

I am currently working on a function that evaluates an array to determine if all elements inside the array are identical. If they are, it should return true; otherwise, it should return false. However, I do not want the function to return true/false for each individual element, but rather for the entire array as a whole.

Solution Attempt 1

The following method works, but it provides true/false output for each element in the array:

function isUniform(arr){
    let first = arr[0];
    for (let i = 1; i <arr.length; i++){
        if (arr[0] !== arr[i]){
            console.log(false);
        } else {
            console.log(true);
        }
    }
}

Solution Attempt 2

This method returns true/false initially and then prints true again at the end:

function isUniform(arr){
    let first = arr[0];
    for (let i = 1; i <arr.length; i++){
        if (arr[0] !== arr[i]){
            console.log(false);
        }
    }
    console.log(true);
}

Answer №1

If you need to verify if a specific condition holds true for every element within an array, there's a simple solution that requires minimal code — utilize the array.every method and compare against the first element. The every() method is advantageous as it will terminate early upon encountering a false condition.

var arr1 = [1, 1, 1, 1, 1, 1, 1]
var arr2 = [1, 1, 1, 2, 1, 1, 1]

console.log(arr1.every((n, _, self) => n === self[0]))
console.log(arr2.every((n, _, self) => n === self[0]))

This approach will even return true for an empty array, although this may not always align with your intended logic.

Answer №2

Utilizing the object Set as an alternative approach

new Set(arr).size === 1 // Signifies that all elements are identical.

let checkUniformity = (arr) => new Set(arr).size === 1;

console.log(checkUniformity([4,4,4,4,4]));
console.log(checkUniformity([4,4,4,4,4,5]));

Answer №3

Include a return statement with false and terminate the function. This returned value can be utilized in the future.

function isUniform(arr) {
    let first = arr[0];
    for (let i = 1; i < arr.length; i++) {
        if (arr[0] !== arr[i]) {
            console.log(false);
            return false;
        }
    }
    console.log(true);
    return true;
}

To make use of the return value, remember to also include a return of true at the end.

Answer №4

Experimenting with Array#every. This method checks if all other values in an array are the same as the first value.

function checkUniformity(arr) {
  return arr.every(item => item === arr[0])
}

console.log(checkUniformity([2,2,2,2]));
console.log(checkUniformity([4,4,4,4,4,5]));

Answer №5

The issue lies in the necessity to halt once encountering the initial incorrect element:

function checkUniformity(array){
    let firstElement = array[0]; 
    let isUniform = true;
    for (let index = 1; index < array.length; index++){
        if (array[0] !== array[index]){
            isUniform = false; 
            break;
        }
    } 
    console.log(isUniform);
}

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