Determining when a function is triggered from the JavaScript console

Question

Determining when a function is triggered from the JavaScript console

Is there a way to conceal a function in JavaScript console so that it's inaccessible for calling?

Let me give you some context - let's say I have a JavaScript function that adds records to a database using Ajax. The issue is, anyone can call this function from the console and add numerous records to the database at will. I need the function to only be usable within the web application itself and not accessible from the console. I've tried obfuscating the code to hide it, but even then, the function can still be located within Google Chrome's JavaScript console.

javascript ajax function console hide

Answer 1

Answer №1

No matter how much you try to disguise and conceal your code, any javascript that can run on the client side can also be executed in the console. To truly secure your functions, it's crucial to implement permissions and security checks on the server side.

However, one technique is to restructure your code within an immediately invoked function expression to make it less accessible from the console:

(function() {
    var myUncallableFunction = function() { alert('meow'); }
})();

The function myUncallableFunction will only be callable from within its parent function as it's a local variable confined to that scope.

Yet, you can still invoke this function within its parent like so:

(function() {
    var myUncallableFunction = function() { alert('meow'); }
    myUncallableFunction();
})();

Answer 2

No matter how much you try to disguise and conceal your code, any javascript that can run on the client side can also be executed in the console. To truly secure your functions, it's crucial to implement permissions and security checks on the server side.

However, one technique is to restructure your code within an immediately invoked function expression to make it less accessible from the console:

(function() {
    var myUncallableFunction = function() { alert('meow'); }
})();

The function myUncallableFunction will only be callable from within its parent function as it's a local variable confined to that scope.

Yet, you can still invoke this function within its parent like so:

(function() {
    var myUncallableFunction = function() { alert('meow'); }
    myUncallableFunction();
})();

Determining when a function is triggered from the JavaScript console

Answer №1

Similar questions

Sending a JavaScript string to a PHP script from a Chrome extension content script

Having trouble with AES decryption on my nodeJS/ExpressJS server backend

Updating a specific field within an array in a Meteor object using MongoDB

The Vue component should trigger the display of data in a Bootstrap modal based on the row of the button that was

Is it possible to transmit an image using ajax and php without using a form or input type file?

When a base html tag is dynamically added, the browser mistakenly loads assets twice

Discovering if an input field is read-only or not can be achieved by using Selenium WebDriver along with Java

Is there a way to retrieve data from three different Bookshelf.js models in a single query?

Tips for resolving a double click issue with a jQuery slide up/down animation

How can I merge these two Observables in Angular to create an array of objects?

Displaying Dynamic Content in React Table Rows Based on Conditions

Guide on parsing the obj variable into a webix .show() modal?

Obtain an Instance of a Class Using a Decorator

Pattern matching to verify a basic number within the range of [0-6]

The performance of the Ajax Jquery remove function leaves something to be desired

How to effectively manage and utilize user queries with jQuery FlexBox to process submitted forms

Interact with WebBrowser Control to Retrieve Document Elements Post-AJAX Request and Handle Null Exceptions

The accuracy of real-time visitor numbers in Google Analytics is often unreliable

What methods can a controller use to verify the legitimacy of the scope?

Can you explain the distinction between $and and $all in this specific scenario?