I am attempting to determine if a password string includes any special characters.
I am trying to achieve this using the code below:
const passwordArr = "A1b2c3d4e5!@#".split("");
const specialChar = "~!@#$%^&*_-+=`|(){}[]:;\"'<>,.?/";
const hasSpecLet = passwordArr.some((letter) => {
specialChar.includes(letter);
});
Unfortunately, the result of hasSpecLet is false.
Make sure to include the return statement in the function you are passing to some():
const checkSpecialLetter = passwordArr.some((letter) => {
return specialChar.includes(letter);
});
Alternatively, you can use a shorter version (without curly braces):
const checkSpecialLetter = passwordArr.some(letter => specialChar.includes(letter));
For more information, visit MDN
When utilizing { } within an arrow function, it is necessary to include the return keyword; otherwise, values are automatically returned.
const passwordArr = "A1b2c3d4e5!@#".split("");
const specialChar = "~!@#$%^&*_-+=`|(){}[]:;\"'<>,.?/";
const hasSpecLet = passwordArr.some((letter) => {
return specialChar.includes(letter);
});
console.log(hasSpecLet);Implementing this minor adjustment will ensure functionality -
const passwordArr = "A1b2c3d4e5!@#".split("");
const specialChar = "~!@#$%^&*_-+=`|(){}[]:;\"'<>,.?/";
const hasSpecLet = passwordArr.some((letter) =>
specialChar.includes(letter)
);
console.log(hasSpecLet)The modification mentioned above guarantees that the output of specialChar.includes(letter) is utilized in the main function to provide the final outcome.
In your scenario, if none of the characters resulted in a true value, you would consistently receive false as the result
Utilizing some() in combination with include()
const includesSpecial = passwordArr.some((char) => specialChar.includes(char))
Applying intersection technique
const includesSpecial = passwordArr.filter(val => specialChar.split('').includes(val)).length !== 0
To ensure proper functionality, it is essential to utilize the return keyword as arrow functions require curly braces:
const passwordArr = "A1b2c3d4e5!@#".split("");
const specialChar = "~!@#$%^&*_-+=`|(){}[]:;\"'<>,.?/";
const hasSpecLet = passwordArr.some((letter) => {
return specialChar.includes(letter);
});
console.log(hasSpecLet);Alternatively, you can achieve the same result by employing the following method:
const passwordArr = "A1b2c3d4e5!@#".split("");
const specialChar = "~!@#$%^&*_-+=`|(){}[]:;\"'<>,.?/";
const hasSpecLet = passwordArr.some((letter) =>
specialChar.includes(letter)
);
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