Determine whether a variable includes an alphabetic character

I need to eliminate any results from an array that include alphabetic characters. To do this, I am using the following code:

if(gtin.toString().length != 13 || /[a-z\-]+/ig.test(gtin) == true) {
    gtin = "null";
}

Although it works for some variables, there are cases where it does not work. For example:

  • CS230
  • C1
  • L3940-noir

Despite using the code above, these variables with alphabets still remain in the array. Any insights on why this might be happening would be greatly appreciated. Thank you!

javascriptarraysregexgoogle-sheets

Answer №1

To create a regular expression, you must combine digits and anchor it:

var example = [
    'abc',
    'CS230',
    'C1',
    'L3940-noir',
    'ab::cd'
];
console.log(example.map(function (item) {
  return item +': '+/^[a-z0-9-]+$/ig.test(item);
}));

Answer №2

This is not a traditional response, but rather an example demonstrating that it does indeed function correctly.

var texts = ['CS230','C1', 'L3940-noir', '1231231231231', '/()!!!###&&&+', 'ABCDEFGHIJKLM', '0123456s78901'];

texts.forEach(function(gtin) {
          
  if(gtin.toString().length != 13 || /[a-z\-]+/ig.test(gtin) == true) {
    gtin = "null";
  }
  document.write(gtin + '<br/>');
});

After reviewing this code snippet, you will notice that all examples are marked as null or "rejected" (as you suggested). The script only accepts strings that are exactly 13 characters long and do not contain any letters.

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