Determine the total of all numbers contained within a multi-layered array

Question

Determine the total of all numbers contained within a multi-layered array

In my nested array setup, it appears as follows:

let scores = [  
[[2, 1, 0], [2, 1, 0]],  
[[4, 2, 0]],  
[[4, 2, 0]],  
[[4, 2, 0],[2, 1, 0]]  
]

The main goal here is to identify the highest value in each sub-array (while summing up the highest values in arrays that contain multiple arrays, such as within the first array, [[2,1,0],[2,1,0]], where we need to add up the highest values of each array resulting in 2+2.) One approach I'm considering is to either use shift() on the initial value of each array OR utilize slice()/remove to extract the lower values. This would transform my current array into this format:

newScores = [[[2],[2]], [4], [4], [[4],[2]]]

Ultimately, what I aim to achieve is represented by: output = [[4], [4], [4], [6]]

I am hopeful for some guidance in this matter! Thank you!

javascript arrays nested

Answer 1

Answer №1

To solve this problem, you must first loop through the parent array, and for each sub-array within it, iterate over its elements to find the maximum number in each sub-array. Then, add up these maximum numbers for each child array and finally store the totals in a new output array.

let scores = [  
[[2, 1, 0], [2, 1, 0]],  
[[4, 2, 0]], 
[[4, 2, 0]],  
[[4, 2, 0],[2, 1, 0]]  
]

var output = [];
scores.forEach(function(score) {
  var total = 0
  score.forEach(function(arr) {
    total += arr.reduce(function(a, b) { return Math.max(a, b); }); 
  })
  output.push(total);
})

console.log(output); // results in [4,4,4,6]

Answer 2

To solve this problem, you must first loop through the parent array, and for each sub-array within it, iterate over its elements to find the maximum number in each sub-array. Then, add up these maximum numbers for each child array and finally store the totals in a new output array.

let scores = [  
[[2, 1, 0], [2, 1, 0]],  
[[4, 2, 0]], 
[[4, 2, 0]],  
[[4, 2, 0],[2, 1, 0]]  
]

var output = [];
scores.forEach(function(score) {
  var total = 0
  score.forEach(function(arr) {
    total += arr.reduce(function(a, b) { return Math.max(a, b); }); 
  })
  output.push(total);
})

console.log(output); // results in [4,4,4,6]

Answer 3

Answer №2

 let finalScores = scores.map(groups =>
     groups.map((total, data) => total + Math.max(...data), 0)
);

Answer 4

 let finalScores = scores.map(groups =>
     groups.map((total, data) => total + Math.max(...data), 0)
);

Answer 5

Answer №3

To achieve this task, utilize the map(), reduce(), and Math.max functions alongside the spread syntax ....

let scores = [  
  [[2, 1, 0], [2, 1, 0]],  
  [[4, 2, 0]],  
  [[4, 2, 0]],  
  [[4, 2, 0],[2, 1, 0]]  
]  

const result = scores.map(a => a.reduce((r, e) => {
  return +r + Math.max(...e)
}, []))

console.log(result)

Answer 6

To achieve this task, utilize the map(), reduce(), and Math.max functions alongside the spread syntax ....

let scores = [  
  [[2, 1, 0], [2, 1, 0]],  
  [[4, 2, 0]],  
  [[4, 2, 0]],  
  [[4, 2, 0],[2, 1, 0]]  
]  

const result = scores.map(a => a.reduce((r, e) => {
  return +r + Math.max(...e)
}, []))

console.log(result)

Answer 7

Answer №4

const gameResults = [  
[[2, 1, 0], [2, 1, 0]],  
[[4, 2, 0]],  
[[4, 2, 0]],  
[[4, 2, 0],[2, 1, 0]]  
]

function calculateScores(arr){
   let finalScores=[];
   let counter = 0;
   for(let i=0;i<arr.length;i++){
       if(arr[i].length>1){
           var a = [Math.max(...arr[i][counter])];
           var b = [Math.max(...arr[i][counter+1])];
        finalScores.push(a.map((ax,bx)=>ax+b[bx]));
       }
       if(arr[i].length===1){
            finalScores.push([Math.max(...arr[i][counter])]);

       }


   }
   return finalScores;

}
calculateScores(gameResults);

Answer 8

const gameResults = [  
[[2, 1, 0], [2, 1, 0]],  
[[4, 2, 0]],  
[[4, 2, 0]],  
[[4, 2, 0],[2, 1, 0]]  
]

function calculateScores(arr){
   let finalScores=[];
   let counter = 0;
   for(let i=0;i<arr.length;i++){
       if(arr[i].length>1){
           var a = [Math.max(...arr[i][counter])];
           var b = [Math.max(...arr[i][counter+1])];
        finalScores.push(a.map((ax,bx)=>ax+b[bx]));
       }
       if(arr[i].length===1){
            finalScores.push([Math.max(...arr[i][counter])]);

       }


   }
   return finalScores;

}
calculateScores(gameResults);

Determine the total of all numbers contained within a multi-layered array

Answer №1

Answer №2

Answer №3

Answer №4

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