Determine if multiple strings contain each other with JavaScript

Question

Determine if multiple strings contain each other with JavaScript

I have a scenario where I am dealing with three strings that contain comma-separated numbers.

var str1 = "1,5,3";
var str2 = "2,5,1";
var str3 = "3,2,1,5";

My objective is to find the common elements between all three strings. The expected output should be:

var result = 1,5;

If I only have two strings, I already have a logic in place which splits the string and checks for common elements:

var array = str2.split(',');
for(var item in array) {
var contains = (str1.indexOf(array[item]) > -1);
if(contains == 1) {
    var result = array[item] + ',';
    getele2 += result;
    geteleresult = getele2.replace(/\,$/, '');
  }
}
alert(geteleresult);

However, when dealing with multiple strings, I am unsure of how to apply similar logic for sorting. If you have any ideas or suggestions, please feel free to provide them. Thank you!

javascript for-loop foreach

Answer 1

Answer №1

Here is a solution using this custom function and logic:

function findCommonNumbers() {
    var nums = {};
    var numArgs = arguments.length;
    for (var i = 0; i < numArgs; i++) {
        var currentArg = arguments[i];
        var foundValues = {};

        var argSplit = currentArg.split(",");
        for (var j = 0; j < argSplit.length; j++) {
            var value = argSplit[j];
            if (!(value in foundValues)) {
                foundValues[value] = 1;
                if (!(value in nums)) {
                    nums[value] = 0;
                }
                nums[value]++;
            }
        }
    }

    var result = [];
    for (var key in nums) {
        if (nums[key] === numArgs) {
            result.push(key);
        }
    }
    return result;
}

DEMO: http://jsfiddle.net/AbCdEf/2/

This function allows you to input multiple string variables containing comma-separated numbers, and it will output the common numbers among them.

Answer 2

Here is a solution using this custom function and logic:

function findCommonNumbers() {
    var nums = {};
    var numArgs = arguments.length;
    for (var i = 0; i < numArgs; i++) {
        var currentArg = arguments[i];
        var foundValues = {};

        var argSplit = currentArg.split(",");
        for (var j = 0; j < argSplit.length; j++) {
            var value = argSplit[j];
            if (!(value in foundValues)) {
                foundValues[value] = 1;
                if (!(value in nums)) {
                    nums[value] = 0;
                }
                nums[value]++;
            }
        }
    }

    var result = [];
    for (var key in nums) {
        if (nums[key] === numArgs) {
            result.push(key);
        }
    }
    return result;
}

DEMO: http://jsfiddle.net/AbCdEf/2/

This function allows you to input multiple string variables containing comma-separated numbers, and it will output the common numbers among them.

Answer 3

Answer №2

Consider this straightforward method:

function findCommonStrings() {
    var argumentsArray = [].slice.call(arguments),
        commonStrings = [], index;

    for (index = 1; index < argumentsArray.length; index++) {
        commonStrings = argumentsArray[index].match(RegExp((commonStrings.length ? commonStrings : argumentsArray[0].split(',')).join('|'), 'g'));
    }

    return commonStrings;
}

http://jsfiddle.net/kUqJb/

This approach is simple and can handle any number of input strings. For example:

var result = findCommonStrings(string1, string2, string3, string4);

Answer 4

Consider this straightforward method:

function findCommonStrings() {
    var argumentsArray = [].slice.call(arguments),
        commonStrings = [], index;

    for (index = 1; index < argumentsArray.length; index++) {
        commonStrings = argumentsArray[index].match(RegExp((commonStrings.length ? commonStrings : argumentsArray[0].split(',')).join('|'), 'g'));
    }

    return commonStrings;
}

http://jsfiddle.net/kUqJb/

This approach is simple and can handle any number of input strings. For example:

var result = findCommonStrings(string1, string2, string3, string4);

Answer 5

Answer №3

One way to find common elements in multiple arrays is by using the indexOf() method.

var array1 = "1,5,3".split(',');
var array2 = "2,5,1".split(',');
var array3 = "3,2,1,5".split(',');
var output = [];

for(var i=0; i<array1.length; i++) {
    if(array2.indexOf(array1[i]) >= 0 && array3.indexOf(array1[i]) >= 0) {
        output.push(array1[i]);
    }
}

alert(output);

You can try running this code on JS Fiddle.

Answer 6

One way to find common elements in multiple arrays is by using the indexOf() method.

var array1 = "1,5,3".split(',');
var array2 = "2,5,1".split(',');
var array3 = "3,2,1,5".split(',');
var output = [];

for(var i=0; i<array1.length; i++) {
    if(array2.indexOf(array1[i]) >= 0 && array3.indexOf(array1[i]) >= 0) {
        output.push(array1[i]);
    }
}

alert(output);

You can try running this code on JS Fiddle.

Answer 7

Answer №4

To arrange the values in a specific order, you can store them in an array and use the .sort() method.

var str1 = "10,50,30";
var str2 = "20,50,10";
var str3 = "30,20,10,50";
var getElements = "";
var resultArray = new Array();
var inputArray = str2.split(',');
for(var element in inputArray) {
    var found = (str1.indexOf(inputArray[element]) > -1);
    if(found == 1){
        var value = inputArray[element];
        resultArray.push(value);
    }
}
alert(resultArray.sort());

Check out the demonstration on JSFiddle: Demo

You can view the code here: http://jsfiddle.net/jvaibhav/BsFPW/

Answer 8

To arrange the values in a specific order, you can store them in an array and use the .sort() method.

var str1 = "10,50,30";
var str2 = "20,50,10";
var str3 = "30,20,10,50";
var getElements = "";
var resultArray = new Array();
var inputArray = str2.split(',');
for(var element in inputArray) {
    var found = (str1.indexOf(inputArray[element]) > -1);
    if(found == 1){
        var value = inputArray[element];
        resultArray.push(value);
    }
}
alert(resultArray.sort());

Check out the demonstration on JSFiddle: Demo

You can view the code here: http://jsfiddle.net/jvaibhav/BsFPW/

Answer 9

Answer №5

To make it simpler, consider storing the strings in an array at the beginning. The code below is a solution that can handle checking more than three strings without requiring any modifications.

str[0] = "4,6,2";
str[1] = "5,3,9";
str[2] = "7,8,5,1";

var matches = '';
for(var i=0;i<str.length-1;i++) {
    if(i==0)
        var str1 = str[i].split(',');
    else
        var str1 = matches.split(',');
    var str2 = str[i+1].split();
    var newMatches = '';
    for(var item in str2) {
        var contains = (str1.indexOf(array[item]) > -1);
        if(contains == 1) {
            var result = array[item]+',';
            newMatches += result;
        }
    }
    matches = newMatches.replace(/\,$/, '');
}

return matches;

Answer 10

To make it simpler, consider storing the strings in an array at the beginning. The code below is a solution that can handle checking more than three strings without requiring any modifications.

str[0] = "4,6,2";
str[1] = "5,3,9";
str[2] = "7,8,5,1";

var matches = '';
for(var i=0;i<str.length-1;i++) {
    if(i==0)
        var str1 = str[i].split(',');
    else
        var str1 = matches.split(',');
    var str2 = str[i+1].split();
    var newMatches = '';
    for(var item in str2) {
        var contains = (str1.indexOf(array[item]) > -1);
        if(contains == 1) {
            var result = array[item]+',';
            newMatches += result;
        }
    }
    matches = newMatches.replace(/\,$/, '');
}

return matches;

Answer 11

Answer №6

Recursively calling a function is possible-

Once you identify the elements common in the first two strings,

You can then compare these commons to the following string, and continue this process,

Depending on how many arguments are passed to the function.

This scenario illustrates that it will yield two '5's if all strings contain two comma separated instances of '5'. (It is important to note that they do not have to be numbers; strings work equally well.)

function inCommon(s1, s2){
    var L1= s1.length, L2= s2.length, rx, 
    A1,  next, next1, next2, least, common= [];
    A1= (L1<= L2)? s1.split(','):s2.split(',');

    for(var i= 0, L= A1.length; i<L; i++){
        next= A1[i];
        rx= RegExp('(^|,)'+next+'(,|$)', 'g');
        next1= (s1.match(rx) || []).length;
        next2= (s2.match(rx) || []).length;
        least= Math.min(next1, next2);
        while(least--) common.push(next);
    }
    if(arguments.length>2 && common.length){
        var a= common.slice.call(arguments, 2);
        a.unshift(common.join(','));
        return inCommon.apply(window, a);
    }
    return common;
}
var str1= "1,5,3";
var str2= "2,5,1";
var str3= "3,2,1,5";

inCommon(str1, str2, str3)

/*  returned value: (Array)
1,5
*/

Answer 12

Recursively calling a function is possible-

Once you identify the elements common in the first two strings,

You can then compare these commons to the following string, and continue this process,

Depending on how many arguments are passed to the function.

This scenario illustrates that it will yield two '5's if all strings contain two comma separated instances of '5'. (It is important to note that they do not have to be numbers; strings work equally well.)

function inCommon(s1, s2){
    var L1= s1.length, L2= s2.length, rx, 
    A1,  next, next1, next2, least, common= [];
    A1= (L1<= L2)? s1.split(','):s2.split(',');

    for(var i= 0, L= A1.length; i<L; i++){
        next= A1[i];
        rx= RegExp('(^|,)'+next+'(,|$)', 'g');
        next1= (s1.match(rx) || []).length;
        next2= (s2.match(rx) || []).length;
        least= Math.min(next1, next2);
        while(least--) common.push(next);
    }
    if(arguments.length>2 && common.length){
        var a= common.slice.call(arguments, 2);
        a.unshift(common.join(','));
        return inCommon.apply(window, a);
    }
    return common;
}
var str1= "1,5,3";
var str2= "2,5,1";
var str3= "3,2,1,5";

inCommon(str1, str2, str3)

/*  returned value: (Array)
1,5
*/

Determine if multiple strings contain each other with JavaScript

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

Similar questions

Preserving the active tab in JQuery while dynamically regenerating tabs due to database updates

Creating environment-agnostic builds with the Vue webpack template

The Flask server push appears to be functioning correctly, yet the EventSource.onmessage event is not triggering as expected

Upon exiting the page, save the initial array in storage. However, the back button will load the last committed array

Enhancing JavaScript Variables Through Dynamic Ajax/PHP Interaction

Tips for dividing the rows within an array using the match() function?

Strip away all HTML attributes within a string

Submit form information and navigate to a different webpage without using AJAX

The Node.js server is failing to retrieve information from the AngularJS application

Exploring the application of Redux in various contexts

Issues with Javascript code syntax

Utilizing the Django object array in AngularJS – a comprehensive guide

Empower the user with the ability to interact through touch on dynamically

Tips for implementing validation in a multi-step form as outlined in w3schools tutorial

Join the nested Observables array

Tips for incorporating "are you sure you want to delete" into Reactjs

Locate an item and add it to my online cart for purchase

Retrieving a specific value from a data object using Javascript

Ajax returns with a successful response, yet the specified action is never executed

Breaking down a intricate JavaScript expression in order to reformat it into a different structure